Circumference one = (2R)*pi let that value be 2x
C second = 5x = (2R)*pi * 5 / 2 = (5R)*pi
So Radius one / Radius two = 2 / 5
Area1:Area2=pi(2R)^2:pi(5R)^2=pi(4R^2):pi(25R^2), pi cancel out we get
4R^2:25R^2, now R^2 cancel out and we get ratio of
4:25
Hello there.
What is 0.16666666666 as a fraction
Answer: 1/6
Taking the cubic root of a number is the same as raising that number to the power of 1/3.
Moreover, we have
![64 = 2^6](https://tex.z-dn.net/?f=64%20%3D%202%5E6)
So, we have
![\sqrt[3]{64} = \sqrt[3]{2^6} = (2^6)^{\frac{1}{3}} = 2^{6\cdot\frac{1}{3}} = 2^2 = 4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%20%3D%20%5Csqrt%5B3%5D%7B2%5E6%7D%20%3D%20%282%5E6%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%20%3D%202%5E%7B6%5Ccdot%5Cfrac%7B1%7D%7B3%7D%7D%20%3D%202%5E2%20%3D%204%20)
Answer:
B
Step-by-step explanation:
You must do the math step by step.
y = -3x - 2
Since a < 0 we have a decreasing line, so it can be only the first or the last
And if we solve the equation for y = 0 we have
0 = -3x - 2
3x = -2
x = -2/3
So, the last one is the right