If an angle is 167 degrees, it is an obtuse angle because, it's greater than a 90 degree angle. (right angle) Let me give you some details on why 167 degrees is an obtuse angle. You probably don't remember from your math classes in the past but, when they give you an angle value and they want to know if it's either a right angle, an acute angle, or an obtuse angle, you figure it out by doing these steps:
1. You take a protractor (it's kinda like a ruler, but it measures angles) and measure the angle given to find out the size of it in degrees.
2. Once you have the measured the angle and found the angle's size in degrees, ask yourself whether it's greater than 90 or less than 90.
You want to ask yourself whether the angle measurement you found is greater than 90 or less than 90 because, if the size of the angle is exactly 90 degrees, than the angle you measured is a right angle.
Now if the angle is greater than 90 (91 and Higher), then you know the angle is an obtuse angle. Which means by process of emulation, that if the angle you found is less than 90 (1-89), than the angle is an acute angle.
And that's why a 167 degree angle is an obtuse angle
Did that help you with your question or do you need just a little bit more understanding?
This is a geometric sequence with an initial term of 27 and a common ratio of 1/3
This just means that each term is 1/3 the term preceding it.
Any geometric sequence can be expressed as:
a(n)=ar^(n-1), a=initial term, r=common ratio, n=term number in this case:
a(n)=27(1/3)^(n-1)
I don’t know but I’m learning negative numbers maybe -3
Answer:
an = 7·2^(n-1)
a10 = 3584
Step-by-step explanation:
(a) The terms of the sequence do not have a common difference, but they do have a common ratio. That ratio is 14/7 = 2. The general term of a geometric sequence with first term a1 and common ratio r is ...
an = a1·r^(n-1)
For a1=7 and r=2, the explicit formula is ...
an = 7·2^(n-1)
__
(b) The 10th term is ...
a10 = 7·2^(10 -1) = 7·512
a10 = 3584
(f - g)(x) = f(x) - g(x)
(f - g)(x) = ( f(x) ) - ( g(x) )
(f - g)(x) = (4x^2 - 6) - ( x^2 - 4x - 8)
(f - g)(x) = 4x^2 - 6 - x^2 + 4x + 8
(f - g)(x) = (4x^2-x^2) + 4x + (-6+8)
(f - g)(x) = 3x^2 + 4x + 2
<h3>Answer: Choice D</h3>
