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natita [175]
3 years ago
9

Tractice writing as a qua

Mathematics
1 answer:
Firlakuza [10]3 years ago
3 0

Answer:

  • z = 3x+2
  • z^2 +7z -8 = 0

Step-by-step explanation:

Define ...

  z = 3x+2

Substitute for that expression in the given quadratic:

  z^2 +7z -8 = 0 . . . . . . your equivalent quadratic

_____

This equation is easily solved by factoring:

  (z +8)(z -1) = 0

  z = -8 or +1

Then x can be found from z:

  (z -2)/3 = x

  (-8 -2)/3 = x = -10/3

  (+1 -2)/3 = x = -1/3

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3(x-4)>= 5x+2

Distributing 3 on x-4

3(x)-3(4)>=5x+2

3x-12>=5x+2

Now we need to move x terms together and the numbers together and for that we subtract 5x to both sides and add 12 to both sides

-2x >=14

Now we need to get rid of -2, and for that we divide both sides by -2 and on dividing by negative number, the sign of inequality change , that is

x<=-7

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Given the cosine equation y = 2cos(4x) - 1, What is the midline?
pogonyaev

Answer:

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First you need to rewrite the equation in the form y = mx +b:

2y = x-4

Divide all terms by 2:

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Simplify:

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The slope of the line is 1/2.

A perpendicular line has a slope of the negative reciprocal, which would be -2.

Now using the point slope method:

y - y1 = m(x-x1)

Using the given point of (8,-4) and m = -2

you get:

y +4 = -2(x-8)

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y +4 = -2x +16

Now subtract 4 from both sides to get the final equation:

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Answer:

Step-by-step explanation:

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