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Dmitry_Shevchenko [17]
2 years ago
8

-30=5(x+1)−30=5(x+1) proszę szybką odpowiedź :)

Mathematics
1 answer:
den301095 [7]2 years ago
7 0

Answer:

x = -7

Step-by-step explanation:

The given equation is :

-30=5(x+1)

We need to solve the equation.

Use associative property on RHS.

-30 = 5x+5

Subtract 5 from both the sides.

-30-5 = 5x+5-5

-35 = 5x

x = -7

Hence, the value of x is -7.

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A hockey player knows that the two goal posts of a hockey net are 1.83 meters apart. The player tries to score a goal by shootin
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The distance the player is from the right post is = 5.1 meters

<h3>Calculation of distance using Pythagorean theorem</h3>

The Pythagorean theorem states that the square of the length of the hypotenuse of a right triangle equals the sum of the squares of the lengths of the other two sides.

Formula for the Pythagorean theorem =

a²= b²+c²

From the diagram given,

The hypotenuse (a) = x²

b= 1.82²

c = 4.8²

x² = 1.82² + 4.8²

x²= 3.3124 + 23.04

x²= 26.3524

a= √26.3524

a= 5.1 meters.

Learn more about distance here:

brainly.com/question/2854969

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3 0
1 year ago
Given cos A=<br> 3<br> ―<br> 10<br> and tan A &lt;0, find sin A.
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7 0
1 year ago
What is 3 equivalent ratios for 2/6
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1/3
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3 years ago
Approximate the change in the volume of a sphere when its radius changes from r​ = 40 ft to r equals 40.05 ft (Upper V (r )equal
alexgriva [62]

Answer:

The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.

Step-by-step explanation:

The volume of the sphere (V), measured in cubic feet, is represented by the following formula:

V = \frac{4\pi}{3}\cdot r^{3}

Where r is the radius of the sphere, measured in feet.

The change in volume is obtained by means of definition of total difference:

\Delta V = \frac{\partial V}{\partial r}\Delta r

The derivative of the volume as a function of radius is:

\frac{\partial V}{\partial r} = 4\pi \cdot r^{2}

Then, the change in volume is expanded:

\Delta V = 4\pi \cdot r^{2}\cdot \Delta r

If r = 40\,ft and \Delta r = 40\,ft-40.05\,ft = 0.05\,ft, the change in the volume of the sphere is approximately:

\Delta V \approx 4\pi\cdot (40\,ft)^{2}\cdot (0.05\,ft)

\Delta V \approx 1005.310\,ft^{3}

The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.

7 0
3 years ago
A cylinder has a volume of 360 cubic centimeters. Find the volume of a cone with the same height and diameter as
harina [27]

Formula for the cylinder = V=πr2h

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Description:

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Answer: 120cm³

Hope this helps.

4 0
2 years ago
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