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lubasha [3.4K]
4 years ago
6

What is the multiplicative inverse of -1/5?​

Mathematics
2 answers:
Nata [24]4 years ago
8 0

Answer:

5

Step-by-step explanation:

luda_lava [24]4 years ago
3 0

Answer:

-5/1

Step-by-step explanation:

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Show whether or not the points with coordinates (1,3) (4,2) (-2,6) are vertices of a right triangle
katen-ka-za [31]

Answer:

No

Step-by-step explanation:

See attached

8 0
3 years ago
Find the area of this rectangle.<br> 2<br> 13 cm<br> 口 Icm<br> 7 cm
Brums [2.3K]

Answer:

bro what

Step-by-step explanation:

5 0
3 years ago
Find the x- and y- intercepts of the following equation.
Ivanshal [37]

Answer:

The x-intercept is (4,0)

The y-intercept is (0,-3)

Step-by-step explanation:

Suppose you have a function f:

f = f(x,y) = 0

The x-intercept is the value of x when y = 0.

The x-intercept is the value of y when x = 0.

Solution

We have:

f(x,y) = -3x + 4y = -12

-3x + 4y + 12 = 0

x-intercept

The x-intercept is the value of x when y = 0. So:

-3x + 4(0) + 12 = 0

-3x + 12 = 0*(-1)

3x - 12 = 0

3x = 12

x = \frac{12}{3}

x = 4

The x-intercept is (4,0)

y-intercept

The y-intercept is the value of y when x = 0. So:

-3(0) + 4y + 12 = 0

4y + 12 = 0

4y = -12

y = \frac{-12}{4}

y = -3

The y-intercept is (0,-3)

5 0
3 years ago
The graph below shows the function f(x)=x-3/x2-2x-3. Which statement is true?
BARSIC [14]
1. Domain.

We have x^2-2x-3 in the denominator, so:

x^2-2x-3\neq0\\\\(x^2-2x+1)-4\neq0\\\\(x-1)^2-4\neq0\\\\(x-1)^2-2^2\neq0\qquad\qquad[\text{use }a^2-b^2=(a-b)(a+b)]\\\\(x-1-2)(x-1+2)\neq0\\\\&#10;(x-3)(x+1)\neq0\\\\\boxed{x\neq3\qquad\wedge\qquad x\neq-1}

So there is a hole or an asymptote at x = 3 and x = -1 and we know, that answer B) is wrong.

2. Asymptotes:

f(x)=\dfrac{x-3}{x^2-2x-3}=\dfrac{x-3}{(x-3)(x+1)}=\boxed{\dfrac{1}{x+1}}

We have only one asymptote at x = -1 (and hole at x = 3), thus the correct answer is A)
6 0
3 years ago
Read 2 more answers
PLZ HELP I WILL GIVE THE BRAINLEST AND 22 PTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! An expression is shown below: 6(m + 2 +
n200080 [17]

Answer:

part A: expression 1: 6(8m+2)

          expression 2: 6m+12+42m

Part B: 6(m+2+7m)= 6(8m+2)

combine like terms is 6(m+2+7m), so it is 6(2+8m) or 6(8m+2)

6(8m+2)= 6(8m+2)

Part C: 6m+12+42m=6(m+2+7m)

m=0

6(0+2+7(0))=6(0)+12+42(0)

6(2)= 12

12=12

7 0
4 years ago
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