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Zielflug [23.3K]
3 years ago
14

Lindsay owns a candy store that typically makes all if its sales to tourists visiting a nearby zoo. Why might she decide to set

up a website for online purchase?
A. To earn extra profit from shipping fees.
B. To decrease customers' wait times.
C. To increase the size of the customer base.
D. To increase the security of financial data.
Computers and Technology
2 answers:
andrezito [222]3 years ago
6 0

Answer:

It is C. To increase the size of the customer base.

Explanation:

Apex

AVprozaik [17]3 years ago
3 0
B and A. Both answers are correct
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Write a test program that creates two Rectangle objects—one with width 4 and height 40 and the other with width 3.5 and height 3
BARSIC [14]

Answer:

public class Rectangle {

   private double width;

   private double heigth;

   public Rectangle(double width, double heigth) {

       this.width = width;

       this.heigth = heigth;

   }

   public double getWidth() {

       return width;

   }

   public void setWidth(double width) {

       this.width = width;

   }

   public double getHeigth() {

       return heigth;

   }

   public void setHeigth(double heigth) {

       this.heigth = heigth;

   }

   public double perimeter(double width, double heigth){

       double peri = 2*(width+heigth);

       return peri;

   }

   public double area(double width, double heigth){

       double area = width*heigth;

       return  area;

   }

}

class RectangleTest{

   public static void main(String[] args) {

       //Creating two Rectangle objects

       Rectangle rectangle1 = new Rectangle(4,40);

       Rectangle rectangle2 = new Rectangle(3.5, 35.7);

       //Calling methods on the first Rectangel objects

       System.out.println("The Height of Rectangle 1 is: "+rectangle1.getHeigth());

       System.out.println("The Width of Rectangle 1 is: "+rectangle1.getWidth());

       System.out.println("The Perimeter of Rectangle 1 is: "+rectangle1.perimeter(4,40));

       System.out.println("The Area of Rectangle 1 is: "+rectangle1.area(4,40));

       // Second Rectangle object

       System.out.println("The Height of Rectangle 2 is: "+rectangle2.getHeigth());

       System.out.println("The Width of Rectangle 2 is: "+rectangle2.getWidth());

       System.out.println("The Perimeter of Rectangle 2 is: "+rectangle2.perimeter(4,40));

       System.out.println("The Area of Rectangle 2 is: "+rectangle2.area(4,40));

   }

}

Explanation:

  • Firstly A Rectangle class is created with two fields for width and heigth, a constructor and getters and setters the class also has methods for finding area and perimeters
  • Then a RectangleTest class containing a main method is created and two Rectangle objects are created (Follow teh comments in the code)
  • Methods to get height, width, area and perimeter are called on each rectangle object to print the appropriate value
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Answer:

public static double areaSum(Circle c1, Circle c2){

 double c1Radius = c1.getRadius();

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public static void main(String[] args){

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 Circle c2 = new Circle(8.0);

  areaSum(c1,c2);

 }

Explanation:

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Answer:

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Explain the role of ICT in banks​
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Answer: ICT help banks improve the efficiency and effectiveness of services offered to customers, and enhances business processes, managerial decision making, and workgroup collaborations, which strengthens their competitive positions in rapidly changing and emerging economies.

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The continuous rise of Electronic signatures has made it easier for people to accept signed documents by email or through electronic devices. One good example of electronic signatures is the implementation of digital signatures which broadly encompasses many types of electronic signatures out there. Digital signatures are unique to each signer and follow a standard authentication protocol called PKI. PKI use mathematical algorithms to generate what are known as private and public keys.

A good example is Bob and Jane. Jane sends an eSignature document using her private keys. Bob receives this document with an attached copy of Jane’s public key. The signature will be considered valid if the public key decrypts the signature correctly.

Learn more about eSignatures and electronic signatures.

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