ANSWER
My answer is in the photo above
87,1/2% of 96 = Z Please tell me HOW to do it!
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Answer:
(A) : μ = 22 ;
: μ ≠ 22
(B) Value of the test statistic = -2.69
Step-by-step explanation:
We are given that a local bottler in Hawaii wishes to ensure that an average of 22 ounces of passion fruit juice is used to fill each bottle. He takes a random sample of 65 bottles. The mean weight of the passion fruit juice in the sample is 21.54 ounces. Assume that the population standard deviation is 1.38 ounce.
We have to test the accuracy of the bottling process.
(A) Let, NULL HYPOTHESIS, :
= 22 ounces {means that an average of 22 ounces of passion fruit juice is used to fill each bottle}
ALTERNATE HYPOTHESIS, :
22 ounces {means that an average of 22 ounces of passion fruit juice is used to fill each bottle}
The test statistics that will be used here is One-sample z-test;
T.S. = ~ N(0,1)
where, = sample mean weight of the passion fruit juice = 21.54 ounces
= population standard deviation = 1.38 ounces
n = sample of bottles = 65
(B) So, <u>test statistics</u> =
= -2.69
Hence, the value of test statistics is -2.69.
Answer: d
Step-by-step explanation:
Find the area of the rectangle.
Find the area of the base of the semicircle.
12 in would be the diameter, divide by 2 to get the radius.
Plug this into the formula.
Since we do not have a full circle but a semi one instead, we must divide our result by 2.
Add both areas.
180+56.52=236.52