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laila [671]
2 years ago
13

$1689 invested for 4 years at 3% compounded annually ?

Mathematics
1 answer:
Ira Lisetskai [31]2 years ago
5 0

The amount gotten after $1689 invested for 4 years at 3% compounded annually is $1901

The amount of money gained after an investment is compounded is given by:

A=P(1+\frac{r}{n} )^{nt}

Where P is principal, A is the final amount, r is the rate, n is the number of times compounded per period and t is the time

Given that P = $1689, t = 4, r = 3% = 0.03, n = 1, hence:

A=P(1+\frac{r}{n} )^{nt}\\\\A=1689(1+\frac{0.03}{1} )^{4*1}\\\\A=\$1901

The amount gotten after $1689 invested for 4 years at 3% compounded annually is $1901

Find out more at: brainly.com/question/14295570

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Write the equation of the line in slope-intercept form that has: slope: 3 point: (0, 2) *
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Answer:y = 3x + 2

Step-by-step explanation: y = mx + b

Where m is the slope and b is the y-intercept.  

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Are the following lines parallel, perpendicular, or neither? y= -4/3x - 5 and y= 3/4x - 5
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6 0
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∠R is congruent to ∠G


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OR

You can follow the letters. If the triangle is labeled with the letters or numbers, it is 90% of the time going to be in order of the alphabet or the numerical sequence.

ΔGHI ≅ ΔRST

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4 0
3 years ago
3 squares are positioned to form a triangle. the small square is labeled 6 units, medium square is 8 units, and large square is
LuckyWell [14K]

The area of the square of the leg 6 is 36 square units.

The area of the square of the leg 8 is 64 square units.

The area of the square of the hypotenuse square is 100 square units.

The length of the hypotenuse is 10 units.

Formula Used

Area of square, A = (a)^{2}

Here, a is the length of the side of the square.

Pythagoras Theorem is given as,

h^{2} =p^{2} +b^{2}

Here, h, p, b are the hypotenuse, perpendicular, and the base of a right angle triangle respectively.

Area of the Square of the Leg 6

Length of the edge of the square = 6 units

Area of square = 6*6

= 36 square units

Area of the Square of the Leg 8

Length of the edge of the square = 8 units

Area of square = 8*8

= 64 square units

Area of the Hypotenuse Square and the Length of the Hypotenuse

Applying Pythagoras theorem,

h^{2} = (8)^{2} +(6)^{2}

h^{2} = 64+36

h = \sqrt{100}

h = 10 units

Therefore, the area of the hypotenuse square is 100 square units and the length of the hypotenuse comes out to be10 units.

Learn more about area of square here:

brainly.com/question/1658516

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