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ivolga24 [154]
2 years ago
9

Help me please someone!!! asap

Mathematics
2 answers:
iragen [17]2 years ago
5 0
It’s A, you need to make sure that you’re dividing what’s in the parenthesis and make sure that 3 gets divided into it as well and the 21:-6 is above a division line with three underneath
beks73 [17]2 years ago
3 0

Answer:

I think the answer is A

Step-by-step explanation:

First you would need to subtract 21 and 6, and then divide the difference of that by 3

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A sound wave travels through iron at a rate of 5120 m/s. At what rate does the sound wave travel in km/h
marissa [1.9K]
<span>When converting a number with meters per second to a value with kilometers per second they best way to perform this operation is by using dimensional analysis or the factor label method. You would set up the equation starting with 5120 m/s times 1 km / 1000 m times 3600 s / 1 hr. It would look like this: (5120 m/ 1 s) x (1 km / 1000 m) x (3600 s / 1 hr) Your next step would be multiplying all the top numbers (numerators) together 5120 x 1 x 3600 = 18,432,000 Now multiple on the bottom numbers (denominators) together 1 x 1000 x 1 = 1000 Now you can divide the top product by the bottom product. 18,432,000 / 1000 = 18,432 km/hr is your final answer.</span>
3 0
3 years ago
Carl's property is assessed at $8,500. The property tax rate in his city is 1.35%. What is Carl's property tax?
eduard
Answer is $114.75. This is found by taking 1.35% of 8,500. 
6 0
3 years ago
Read 2 more answers
What is the slope of the line that passes through the points (-2, 6) and (4, - 2)?
Irina-Kira [14]

Step-by-step explanation:

slope(m)= y2-y1/x2-x1

-2-6/4+2

= -8/6

= -4/3

6 0
2 years ago
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I will mark Brainliest
gladu [14]
I think its  A = 4π(7)2
8 0
3 years ago
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Which of the following are solutions to the equation below?
sladkih [1.3K]

Answer:

\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

                  x=3,\:x=-\frac{1}{2}

Step-by-step explanation:

considering the equation

2x^2\:-\:4x\:-\:3\:=\:x

solving

2x^2\:-\:4x\:-\:3\:=\:x

2x^2-4x-3-x=x-x

2x^2-5x-3=0

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=2,\:b=-5,\:c=-3:\quad x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

solving

x=\frac{-\left(-5\right)+\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

x=\frac{5+\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}

x=\frac{5+\sqrt{49}}{2\cdot \:2}

x=\frac{5+7}{4}

x=3

also solving

x=\frac{-\left(-5\right)-\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

x=\frac{5-\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}

x=\frac{5-\sqrt{49}}{4}

x=-\frac{2}{4}

x=-\frac{1}{2}

Therefore,

                 \mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

                  x=3,\:x=-\frac{1}{2}

7 0
3 years ago
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