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777dan777 [17]
3 years ago
8

The diagonal of a square is 2.42 cm. Findthe area of the square.​

Mathematics
1 answer:
OLEGan [10]3 years ago
6 0

Answer:

let \: one \: side \: be \: x \\ x =  \sqrt{ {2.42}^{2}  -  {x}^{2} }  \\ 2 {x}^{2}  = 5.8564 \\  {x}^{2}  = 2.9282 \\ x = 1.71 \: cm \\ area \:  = x \times x \\ area = 1.71 \times 1.71 \\  = 2.92 \:  {cm}^{2}

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No

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3 years ago
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Alexeev081 [22]

Answer:

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Step-by-step explanation:

The given quadratic equation is

5x^2-7x+2=0

Group the constant terms on the right hand side.

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5x^2-7x=-2

Divide through by 5.

x^2-\frac{7}{5}x=-\frac{2}{5}

Add the square of half the coefficient of x., which is (\frac{1}{2}\times- \frac{7}{5})^2=\frac{49}{100} to both sides of the equation.

x^2-\frac{7}{5}x+\frac{49}{100}=-\frac{2}{5}+\frac{49}{100}

The left hand side is now a perfect square.

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Take the square root of both sides;

(x-\frac{7}{10})=\pm \sqrt{\frac{9}{100}}

x-\frac{7}{10}=\pm \frac{3}{10}

x=\frac{7}{10}\pm \frac{3}{10}

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5 0
3 years ago
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Square root of 121 is 11.
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3 years ago
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