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2 years ago

F(x)=x^2. What is g(x)

Mathematics

1 answer:

Arisa [49]2 years ago

7 0

Answer:

Step-by-step explanation:

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1.Encuentra de dos formas diferentes el área de las figuras mostradas en cada literal:

MA_775_DIABLO [31]

Answer:

Cuadrilátero A: $A = y^{2}+4\cdot y +4$

Cuadrilátero B: $A = a^{2}+6\cdot a + 9$

Step-by-step explanation:

Existen dos formas distintas de determinar las áreas de cada cuadrilátero:

(i) Obtener el área de cada cuadrado y sumar los resultados.

(ii) Calcular los lados del cuadrilátero grande y determinar el área.

Cuadrilátero A

Método (i)

$A = y^{2}+2\cdot y +4+2\cdot y$

$A = y^{2}+4\cdot y +4$

Método (ii)

$A = (y+2)\cdot (y+2)$

$A = y^{2}+4\cdot y + 4$

Cuadrilátero B

Método (i)

$A = a^{2}+3\cdot a +9 + 3\cdot a$

$A = a^{2}+6\cdot a +9$

Método (ii)

$A = (a+3)\cdot (a+3)$

$A = a^{2}+6\cdot a + 9$

8 0

2 years ago

What are the potential solutions to the equation 2ln(x+3)=0

skad [1K]

$2\ln(x+3)=0\implies \ln(x+3)^2=0\implies e^{\ln(x+3)^2}=e^0\implies (x+3)^2=1$

Expanding the left side gives

$x^2+6x+9=1\implies x^2+6x+8=0\implies (x+4)(x+2)=0$

which gives two solutions, $x=-4$ and $x=-2$ . But if $x=-4$ , then $\ln(x+3)=\ln(-1)$ , but this number isn't real, so $x=-4$ is an extraneous solution. Meanwhile if $x=-2$ , you get $\ln(-2+3)=\ln1=0$ , so this solution is correct.

"Potential solutions" might refer to both possibilities, but there is only one actual (real) solution.

4 0

3 years ago

Read 2 more answers

Pulease helpp

Bas_tet [7]

Answer:

Step-by-step explanation:

using formula

area of triangle=1/2 × AB×AC×sinA

WHERE AB=10 andAC=15 and sinA=37○

7 0

3 years ago