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2 years ago

I’m not sure if my answers are right but you’re supposed to find the length of AC and QR (simplified)

Mathematics

1 answer:

alexira [117]2 years ago

8 0

Answer:

Let me see and I will try and help

Step-by-step explanation:

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R^2+7r+10/3 / 3-30/r2-5r-50

kvasek [131]

Multiply r^2+7r+10/3 by 3r-30/r^2-5r-50
=( r^2+7r+10)/3 (3r-30)/(r^2-5r-50) 
=(r+2)(r+5)/3 3(r+10)/ (r-10)(r+5) 
=3 (r+2)(r+5)(r+10)/3(r-10)(r+5) 
=(r+2)(r+10)/(r-10)

8 0

2 years ago

Read 2 more answers

Evaluate each expression using order of operations 40-32÷8+5×-2

klio [65]

Answer:

Step-by-step explanation:

40-32÷8+5×-2

40-4+5×-2

40-4+-10

36+-10

6 0

2 years ago

A.) 0.3 B.)0.4 C.)0.5 D.)0.6

love history [14]

Answer:

A) 0.3

Step-by-step explanation:

You need to add all of them together first,

126 + 201 + 107 + 120 + 46 = 600

Out of 600, 201 is e, so 201/600 = 0.335, which is also just 0.3

7 0

2 years ago

Compare. use <, > ,or = to complete the statement

8_murik_8 [283]

> hello there stranger

8 0

3 years ago

Which two values of x are roots of the polynomial below? x^2-3x+5

Gemiola [76]

Given:

Polynomial $x^2-3x+5$

To find:

The values of x.

Solution:

$x^2-3x+5=0$

Quadratic equation formula:

$$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here $a=1, b=-3, c=5$ .

Substitute the values in the formula, we get

$$x=\frac{-(-3) \pm \sqrt{(-3)^{2}-4 \cdot 1 \cdot 5}}{2 \cdot 1}$

$$x=\frac{3 \pm \sqrt{9-20}}{2}$

$$x=\frac{3 \pm \sqrt{-11}}{2}$

$$x=\frac{3 - \sqrt{-11}}{2} \ \text{and} \ x=\frac{3 + \sqrt{-11}}{2}$

Option E and option F are the roots of the polynomial.

The values of x are $x=\frac{3 - \sqrt{-11}}{2} \ \text{and} \ x=\frac{3 + \sqrt{-11}}{2}$ .

7 0

3 years ago