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VashaNatasha [74]
3 years ago
14

Which decimal number is represented by the shaded portion of the model?

Mathematics
2 answers:
deff fn [24]3 years ago
7 0
The person on top might be a scam seen the same url too many times. J
myrzilka [38]3 years ago
3 0
The answer is 0.9
The answer is 0.9
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P1 = (1,5). P2 = (x,2) .p1p2=5 ​
Alex787 [66]

\qquad\qquad\huge\underline{{\sf Answer}}♨

Let's use distance formula :

\qquad \sf  \dashrightarrow \: \sqrt{(x - 1) {}^{2}  +  (2 - 5) {}^{2} } = 5

\qquad \sf  \dashrightarrow \: {(x - 1) {}^{2}  +  ( - 3) {}^{2} } = 5 {}^{2}

\qquad \sf  \dashrightarrow \:(x - 1) {}^{2}  + 9 = 25

\qquad \sf  \dashrightarrow \:(x - 1) {}^{2}  = 16

\qquad \sf  \dashrightarrow \:(x - 1) = 16

\qquad \sf  \dashrightarrow \:(x - 1) =  \pm4

\qquad \sf  \dashrightarrow \:x = 5 \:  \: or \:  \:  - 3

6 0
2 years ago
If you were to graph the point -4 -3 it would fall in the third quadrant true false
Varvara68 [4.7K]

Answer:

false

Step-by-step explanation:

it will fall in 4th quadrant as in 3rd x is +, y is -. and in 4th x is - and y is -

3 0
2 years ago
The lab experiment is repeated again with the same two glass plates and the same sodium lamp but with a different human hair. Th
OleMash [197]

Answer:

diamerer of the hair (t)  3.11 X 10^{-5} m

Step-by-step explanation:

The first dark spot is at the zero location where the glass plates touch. To find the number of dark fringes after first dark fringe, divide 12 cm by 0.75 mm (.075 cm)

12/.075 = 160.0

total number of additional bright fringe is 156 because there is no further portion for extra dark fringe.

diamerer of the hair (t) can be derived as

2nt = (m + .5)*wavelength

2(1.52)(t) = (160.5)(589.3 X 10^{-9})

t = 3.11 X 10^{-5} m

4 0
3 years ago
A reflection and a glide are the same thing. <br> True or false?
snow_tiger [21]
I think its fqalse sure thio
3 0
3 years ago
What is the value of the expression below when a = 5?<br> ​<br> ​ 7a - 4
Ostrovityanka [42]

Answer:

31

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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