For this case we have:
To begin we must graph
, for this:
We do
, then:

So, we have the point 
We do
, then:


So, we have the point
We place both points in a coordinate plane and graph the line. Now, we must find the shaded region that identifies the inequality 
We must replace any point located to the left or to the right of the line. If the inequality is met, then the shaded region will be on the respective side.
We substitute the point

The inequality is met, then the shaded region is to the right of the line.
Answer:
See attached image
Answer:
x
2
+
2
x
−
3
=
0
x
2
−
3
x
=
0
3
x
2
−
15
x
=
0
Step-by-step explanation:
The sum is 160/(1-r)=1280 where r is the common ratio,
1/(1-r)=1280/160=8
Inverting we get 1-r=1/8, r=7/8.
-3x+5y=10 (add 3x on both side)
5y=3x+10 ( divide 5 to each term)
y=3/5x+2
slope is 3/5
y-intercept is 2