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3 years ago

2

Mathematics

2 answers:

lukranit [14]3 years ago

8 0

Answer:

25 , 30

Step-by-step explanation:

x > 50 -28

x > 22

x is greater than 22.

Misha Larkins [42]3 years ago

5 0

Answer:

Step-by-step explanation:

D and E because x must be greater than 23

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Drag the measurements to the containers to show equal length.

Pani-rosa [81]

The measurements that show equal length is 15 yd and 540 in, 195 ft and 2340 in, 5280 yd and 15840 ft

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

1 ft = 12 in; 1 yd = 3 ft and 1 yd = 36 in.

Hence:

15 yd = 15 yd * 36 in per yd = 540 in

195 ft = 195 ft * 12 in per ft = 2340 in

5280 yd = 5280 yd * 3 ft per yd = 15840 ft

The measurements that show equal length is 15 yd and 540 in, 195 ft and 2340 in, 5280 yd and 15840 ft

Find out more on equation at: brainly.com/question/2972832

3 0

2 years ago

PLEASE HELP ASAP 50 PTS + BRAINLIEST TO RIGHT/BEST ANSWER. please only answer if you know for sure!

jeyben [28]

Answer:

D. ∛4a^2 / a

Step-by-step explanation:

∛4a / ∛a^2

= ∛(4a)* ∛a / ∛a^2 * ∛a

= ∛4a^2 / ∛a^3

= ∛4a^2 / a

Answer is D. ∛4a^2 / a

8 0

3 years ago

Read 2 more answers

The shape of the distribution of the time required to get an oil change at a 15-minute oil-change facility is unknown. However,

horsena [70]

Answer:

The mean oil-change time that would there be a 10% chance of being at or below is 15.46 minutes.

Step-by-step explanation:

We are given that records indicate that the mean time is 16.2 minutes, and the standard deviation is 3.4 minutes.

On a typical Saturday, the oil-change facility will perform 35 oil changes between 10 A.M. and 12 P.M. Assuming that data follows normal distribution.

Let $\bar X$ = sample mean time

The z score probability distribution for sample mean is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean time = 16.2 minutes

$\sigma$ = standard deviation = 3.4 minutes

n = sample size = 35 oil changes

Now, the mean oil-change time that would there be a 10% chance of being at or below is given by;

P(X $\leq$ x) = 0.10 {where x is required mean oil-change time}

P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{x-16.2}{\frac{3.4}{\sqrt{35} } }$ ) = 0.10

P(Z $\leq$ $\frac{x-16.2}{\frac{3.4}{\sqrt{35} } }$ ) = 0.10

Now, in the z table the critical value of X which represents the below 10% of the probability area is given as -1.282, that means;

$\frac{x-16.2}{\frac{3.4}{\sqrt{35} } }$ = -1.282

x - 16.2 = $-1.282 \times {\frac{3.4}{\sqrt{35} } }$

x = 16.2 - 0.74 = 15.46 minutes

Hence, the mean oil-change time that would there be a 10% chance of being at or below is 15.46 minutes.

8 0

3 years ago

An ordinary (fair) die is a cube with the numbers through on the sides (represented by painted spots). Imagine that such a die i

lana [24]

Answer:

a. 5/12

b. 7/18

Step-by-step explanation:

In this question, we are interested in computing the probabilities.

Firstly, we need to get the sample space of the results. This refer to all possible results that can emerge from the rolling of the two die.

This can be found in the attachment.

What is important to know however is that the total number of possible results is 36;

so let’s compute;

a. For a, let’s circle all sums which are greater than 7 ;

We can see a total of 16 circled sums;

So the probability is 15/36 = 5/12

b. Sum divisible by 4 or 6 or both

Let’s make a circle again ;

So we have a total of 14

So the probability will be 14/36 = 7/18

6 0

4 years ago

(2/3) / (-1/2) How do I divide these 2 fractions?

dsp73

Answer:

Step-by-step explanation:

2/3*(-2/1)

$-\frac{4}3}$

Hope it helps! Please mark Brainliest if it does!

4 0

3 years ago

Read 2 more answers