The main idea is using the Pythagorean formula to find the length of line segment
.
Alr so you use the formula 
is already given and is 
and
is 
So using algebraic rules you'll get
as:

Now using the formula:
, you can find the area of tri ABD and CBD which would be
and
so add them up and you get
!
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➷ As you can tell, the ratio of the lengths is 2 : 1 (the length of a is twice the length of b)
The ratio for area would be the squared version of the length ratio
2^2 = 4
1^1 = 1
The ratio for area is 4 : 1
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Answer:
c. 441ft^2
Step-by-step explanation:
Area is height times length and since it's a square, safe to say that the sides are equal in length. So square root both of the given areas of the 2 square:
= 29
= 20
Now u have side b and c of the triangle, it's a right triangle so use the Pythagorean theorem a^2 + b^2 = c^2
a^2 + b^2 = c^2
a^2 + 20^2 = 29^2
a^2 + 400 = 841
subtract 4 from both sides
a^2 = 441
square root both sides

a = 21
Now the side a of the triangle is also a side of the small square therefore
21^2 = 441
I believe d is the answer please contact me if its wrong
Answer:
minimum
Step-by-step explanation:
Given a quadratic in standard form f(x) = ax² + bx + c ( a ≠ 0 )
• If a > 0 then vertex is a minimum
• If a < 0 then vertex is a maximum
f(x) = 3x² + 5x + 2 ← is in standard form
with a = 3
Since a > 0 then vertex is a minimum