ABC is a right triangle in which ∠B = 90°. D is a point on BC such that DC=AB. DE and BF are perpendicular to AC. If BF = 4cm, t
hen CE+BF =________
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Hi there!
Parabola x² = 12y
→ x² = 4ay
→ 4a = 12
→ a = 12÷4
→ a = 3
So, the co-ordinates of the focus is:-
S(0,a)=(0,3)
→ Let AB be the latus rectum of the given parabola.
→ Coordinates of end-points of latus rectum are (-2a,a), (2a,a)
→ Coordinates of A are (-6,3), while B's coordinates are (6,3).
→ ∆OAB are O(0,0), A(-6,3), B(6,3)
Area of ∆OAB is :-
(<em>Solving part attached as image</em>)
=> <u>1</u><u>8</u><u> </u><u>unit</u>² is the required answer.
