Answer:
See explanation
Step-by-step explanation:
The function AJ graphed is
.
When x=0, we get ![f(0)=-(0+2)^2-1](https://tex.z-dn.net/?f=f%280%29%3D-%280%2B2%29%5E2-1)
This implies ![f(0)=-4-1=-5](https://tex.z-dn.net/?f=f%280%29%3D-4-1%3D-5)
When x=1![f(1)=-(1+2)^2-1=-3^2-1=-9-1=-10](https://tex.z-dn.net/?f=f%281%29%3D-%281%2B2%29%5E2-1%3D-3%5E2-1%3D-9-1%3D-10)
All the values we evaluated between -5 and 5 gives negative value.
This means that AJ's graph should have turn upside down
Find it out or loose it man
Answer:
222
Step-by-step explanation:
Let me know if it is correct!
The trigonometric equation <span> (sin Θ − cos Θ)^2 − (sin Θ + cos Θ)^3 can be simplified by:
</span>Using x for Θ:
<span>(sinx - cosx)^2 - (sinx + cosx)^2 </span>
<span>= (sin^2 x - 2sinxcosx + cos^2 x) - (sin^2 x + 2sinxcosx + cos^2 x) </span>
<span>= - 2 sinx cosx - 2 sinx cosx </span>
<span>= - 4 sinx cosx </span>
<span>= - 2sin(2x)
</span>
I hope it has come to your help.
Answer:
A is 65 degrees
Step-by-step explanation: