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DIA [1.3K]
3 years ago
13

I will mark brainliest !! write an exponential function for the set of points. picture is below

Mathematics
1 answer:
liq [111]3 years ago
7 0

Answer:

y = 6(2^{x} )

Step-by-step explanation:

Let

y = kb^{x}

When x = 0, y = 6.  So, 6 = kb^{0} = k(1 ) = k

Since k = 6 we have y = 6b^{x}

When x = 1, y = 12.  

So 12 = 6b^{1}  = 6b

b = 2

Therefore, the exponential function is  y = 6(2^{x} )

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Identify the vertical asymptotes of f(x) = quantity x minus 4 over quantity x squared plus 13 x plus 36
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Expression: f(x) = [x - 4] / [x^2 + 13x + 36].

The vertical asympotes is f(a) when the denominator of f(x) is zero and at least one side limit when you approach to a is infinite or negative infinite.

The we have to factor the polynomial in the denominator to identify the roots and the limit of the function when x approachs to the roots.

x^2 + 13x + 36 = (x + 9)(x +4) => roots are x = -9 and x = -4

Now you can write the expresion as: f(x) = [x - 4] / [ (x +4)(x+9) ]

Find the limits when x approachs to each root.

Limit of f(x) when x approachs to - 4 by the right is  negative infinite and limit when x approach - 4 by the left is infinite, then x = - 4 is a vertical asymptote.

Limit of f(x) when x approachs to - 9 by the left is  negative infinite and limit when x approach - 9 by the right is infinite, then x = - 9 is a vertical asymptote.

Answer: x = -9 and x = -4 are the two asymptotes.

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4 years ago
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What is the best approximation of the length of segment QS? (Note: cos 80° = 0.17)
matrenka [14]

Answer: QS=11.8cm


Step-by-step explanation:

1. You have the following information:

- The lenght of RS is 2 centimeters.

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2. Therefore, you can calculate the lenght of the segment QS as following:

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3. Substitute values and solve for QS:

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4. To the nearest tenth:

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