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Delicious77 [7]
3 years ago
7

Please help! THESE ARE ALL MY POINTS! The ribbon on a spool is 10 yards long. How many 6-inch pieces of ribbon can be cut from t

he spool? (Conversion rate: 1 yd= 36 in)
Mathematics
1 answer:
Inessa05 [86]3 years ago
3 0

Answer:

10*36 is 360

360/6 is 60

Step-by-step explanation:

Good luck!

Don't forget you are smart, amazing, and loved!

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PLEASE HELP ME RUNNING OUT OF TIME!!!
elena-14-01-66 [18.8K]

Answer:

I am not sure of the answer but it is between A and C but my final answer is gonna be C.

8 0
3 years ago
The force (F) needed to cause the acceleration (a) of an object of mass, m, is given by the equation, F=ma where m is the object
KATRIN_1 [288]

From Newton’s Second Law of Motion, the force needed to accelerate a moving object of mass m at acceleration a is given by ;

F = ma

In this case, m = 5kg, a = 6m/s^2 and we want to find F

F = 5 x 6

F = 30N

Therefore, a force of 30N is needed to accelerate a 5kg object at 6m/s^2.

8 0
3 years ago
NEED HELP WORTH 100 POINTS SHOW YOUR WORK PLEASE
tia_tia [17]

Answer:

Q1:

-5\sqrt{27c^2}

-5\sqrt{27}\sqrt{c^2}

-5\times\sqrt{9} \sqrt{3} \sqrt{c^2}

-5\times3\sqrt{3}\sqrt{c^2}

-5\times3\sqrt{3}c

-15\sqrt{3}c

Q2:

5\sqrt{72}-3\sqrt{32}

5\sqrt{36} \sqrt{2} -3\sqrt{16} \sqrt{2}

5\times6\sqrt{2}-3\times4\sqrt{2}

30\sqrt{2}-12\sqrt{2}

18\sqrt{2}

Q3:

\sqrt{108yz}+3\sqrt{98yz}+2\sqrt{75yz}

\sqrt{36} \sqrt{3} \sqrt{yz} +3\sqrt{49} \sqrt{2} \sqrt{yz} +2\sqrt{25} \sqrt{3} \sqrt{yz}

6\sqrt{3}\sqrt{yz}+21\sqrt{2}\sqrt{yz}+10\sqrt{3}\sqrt{yz}

16\sqrt{3}\sqrt{yz}+21\sqrt{2}\sqrt{yz}

Q4:

\sqrt{15n^2}\sqrt{10n^3}

\sqrt{15}n\sqrt{10n^3}

\sqrt{15}n\sqrt{10}\sqrt{n^2}\sqrt{n}

\sqrt{15}\sqrt{10}n^2\sqrt{n}

\sqrt{5}\sqrt{3}\sqrt{5}\sqrt{2}n^2\sqrt{n}

5\sqrt{3}\sqrt{2}n^2\sqrt{n}

5\sqrt{6}n^2\sqrt{n}

Q5:

\frac{\sqrt{3x^2y^3}}{4\sqrt{5xy^3}}

\frac{\sqrt{3}xy\sqrt{y}}{4\sqrt{5}y\sqrt{x}\sqrt{y}}

Cancel off \sqrt{x}:

\frac{\sqrt{3}y\sqrt{x}\sqrt{y}}{4\sqrt{5}y\sqrt{y}}

Cancel off y:

\frac{\sqrt{3}\sqrt{x}\sqrt{y}}{4\sqrt{5}\sqrt{y}}

Cancel off \sqrt{y} :

\frac{\sqrt{3}\sqrt{x}}{4\sqrt{5}}

Multiply \sqrt{5} on the numerator and denominator:

\frac{\sqrt{3}\sqrt{x}\sqrt{5}}{4\sqrt{5}\sqrt{5}}

\frac{\sqrt{15}\sqrt{x}}{20}

5 0
3 years ago
If the area of a square is 100 cm2, what is the perimeter?<br>​
Vitek1552 [10]

Answer:

40

Step-by-step explanation:

To find the perimeter, first we need to find the side lengths.

If 100 cm is the area then we need to find what number squared is 100

10 x 10 = 100

So 10 is the side length. P= s + s + s +s

10 + 10 + 10 +10 = 40

6 0
3 years ago
What is the 10th term in the pattern with the formula 9n + 9?
Studentka2010 [4]
A(10) = <span>9(10) + 9= 90+9 =99

---------------------------------------------</span>
6 0
3 years ago
Read 2 more answers
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