7. Look at the picture.

A graduated commission employee makes 3.5% interest on the first $50,000 in sales and 6.5% interest on all sales over $50,000. W

Dominik [7]

b. (0.035)(50,000) + (0.065)(31,500)

3 0

3 years ago

Read 2 more answers

Printing machine A and printing machine B print the same newspaper printout, but machine B prints at half the rate of machine A.

klemol [59]

Answer:

The answer is below

Step-by-step explanation:

Let us assume the rate of printing in machine A is x per hour and the rate for machine B is y. Given that machine B prints at half the rate of machine A, therefore:

y = (1/2)x (1)

Also, both machine produces 200 newspaper printouts, and both operate at different times for a total of 4 hours. Therefore:

200/x + 200/y = 4 (2)

Put y = (1/2)x in equation:

$\frac{200}{x}+\frac{200}{(\frac{1}{2} )x}=4\\ \\ \frac{200}{x}+\frac{400}{x}=4\\\\Multiply\ through\ by\ x:\\\\200+400=4x\\\\4x=600\\\\x=150$

Put x = 150 in equation y:

y=(1/2)150 = 75

Therefore the rate of machine A is 150 newspapers per hour while that of machine B is 75 newspapers per hour

6 0

4 years ago

PLEASE HELP WITH 37 IM MARKING BRAINLIEST TO THE CORRECT ANSWER

Maru [420]

Answer:

Infinitely many solutions

Step-by-step explanation:

-5.9x - 3.7y = -2.1

5.9x + 3.7y = 2.1

If we add these two equations together, -5.9x cancels out 5.9x, -3.7y cancels out 3.7y, and -2.1 cancels out 2.1.

This leaves us with:

0 = 0

Since this is true, that means there are infinite solutions.

5 0

3 years ago

Un jardín rectangular de 50 cm de largo por 34 m de ancho está rodeado por un camino de arena uniforme.Halla la anchura de dicho

Anastasy [175]

Answer:

5.85 m

Step-by-step explanation:

The width of the sand road can be calculated knowing its area and the dimensions of the rectangular garden as follows:

$A_{g} = a.b$

Where:

Ag: is the area of the rectangular garden

a: is the length of the rectangular garden = 50 cm = 0.5 m

b: is the width of the rectangular garden = 34 m

$A_{s} = 540 m^{2}$

Where:

As: is the area of the sand road

The relation between the area of the sand road and the area of the rectangular garden is the following:

$A_{s} + A_{g} = (a+2x)*(b+2x)$

$540 m^{2} + 0.5m*34m = ab + 2ax + 2bx + 4x^{2}$

$557 m^{2} = ab + 2x(a + b) + 4x^{2}$

$557 m^{2} - 17m^{2} - 2x(34.5 m) - 4x^{2} = 0$

$540 - 69x - 4x^{2} = 0$

By solving the above equation for x we have two solutions:

x₁ = -23.10 m

x₂ = 5.85 m

Taking the positive value, we have that the width of the sand road is 5.85 m.

I hope it helps you!

7 0

3 years ago

This question is realy hard so helpp

LUCKY_DIMON [66]

Answer:

Algebrically the result can be written as -

$9 {x}^{2} + 24x + 16$

Step-by-step explanation:

Let the number be 'x'.

When multiplied by 3 , algebrically it is written as "3x".
When 4 is added to 3x , algebrically it is written as "3x + 4".
When (3x + 4) is squared completely , algebrically it is written as - ${(3x + 4)}^{2} = 9 {x}^{2} + 24x + 16$

8 0

3 years ago