$\frac{2x^2+5x+3}{x^2-3x-4}$ divided by $\frac{4x^2+2x-6}{x^2-8x+16}$ is the same thing as multiplying $\frac{2x^2+5x+3}{x^2-3x-4}$ by $\frac{x^2-8x+16}{4x^2+2x-6}$ .

The equation we get is:

$\frac{2x^2+5x+3}{x^2-3x-4}*\frac{x^2-8x+16}{4x^2+2x-6}$

With this equation, we can factor each equation:

$\frac{(x+1)(2x+3)}{(x+1)(x-4)} *\frac{(x-4)(x-4)}{2(x-1)(2x+3)}$

We can cancel out like terms since they would be dividing each other:

$\frac{x-4}{2x-2}$

8 0

3 years ago

Can a pair of numbers have more than one common factor?

Y_Kistochka [10]

Yes! For example, 10 and 20 have 1, 2, 5, & 10 in common ^.^

4 0

3 years ago

For every lion there are 7 giraffes

dimaraw [331]

Answer:

.................

Step-by-step explanation:

hmmm

7 0

2 years ago

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