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bagirrra123 [75]
2 years ago
6

Karen surveyed students in one middle school about their favorite band. Of the 1,156 students in the middle school, 65 sixth-gra

de students were surveyed. More than half of the 65 students said their favorite band is Rhonda and the Gees. Based on the survey, Karen says most middle school students’ favorite band is Rhonda and the Gees. Why is Karen’s statement incorrect? *
(A)Karen surveyed too many students.
(B)Karen’s survey sample was too small.
(C)Karen did not survey any high school students.
(D)Karen did not include enough bands in the survey.
Mathematics
1 answer:
ValentinkaMS [17]2 years ago
3 0
I believe the answer is B.



Explanation: In the problem, it states that “Karen says MOST middle school students’ favorite band is Rhonda and the Gees.” Pay attention to the keyword, most. Only 65 students like Rhonda and the Gees, so it is too small to represent a middle school of 1,156. So, therefore, the answer should be B.
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What is the difference?
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Answer:

<h2>D. \frac{x^{2}+3x-12 }{(x-5)(x+3)(x+7)} \\ or StartFraction x squared + 3 x minus 12 Over (x + 3) (x minus 5) (x + 7) EndFraction</h2>

Step-by-step explanation:

Given the expression \frac{x}{x^{2}-2x-15 } - \frac{4}{x^{2} + 2x - 35 }, the dfference is expressed as follows;

Step1: First we need to factorize the denominator of each function.

\frac{x}{x^{2}-2x-15 } - \frac{4}{x^{2} + 2x - 35 }\\= \frac{x}{x^{2}-5x+3x-15 } - \frac{4}{x^{2} + 7x-5x - 35 }\\= \frac{x}{x(x-5)+3(x-5) } - \frac{4}{x( x+ 7)x-5(x +7) }\\= \frac{x}{(x-5)(x+3) } - \frac{4}{(x-5)(x +7) }\\\\

Step 2: We will find the LCM of the resulting expression

=  \frac{x}{(x-5)(x+3) } - \frac{4}{(x-5)(x +7) }\\= \frac{x(x+7)-4(x+3)}{(x-5)(x+3)(x+7)} \\= \frac{x^{2}+7x-4x-12 }{(x-5)(x+3)(x+7)} \\= \frac{x^{2}+3x-12 }{(x-5)(x+3)(x+7)} \\

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When John bought his new computer he purchased an online computer help service. The help service has a yearly fee of 25.50 and a
Tems11 [23]
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6 0
3 years ago
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<u>Answer:</u>

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<u>Explanation:</u>

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Answer:

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