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serg [7]
3 years ago
6

PLEASE HELP IM ON A TIMED TEST

Mathematics
1 answer:
Mila [183]3 years ago
6 0

Answer:

third term

Step-by-step explanation:

hope this helped

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When z is divided by 6, the remainder is 4. What is the remain-der when z is divided by 2 ?
Aleksandr [31]

Answer:

12

Step-by-step explanation:

So first, when z is divded by 6 we get 4 left.

So an example for z could be 24.

(24 / 6 = 4)

When z is divded by 2, it would be 12

24 / 2 = 12

(I hope this helps and that you have a nice day!)

4 0
3 years ago
A quality-control engineer samples 100 items manufactured by a certain process, and finds that 15 of them are defective. True or
goldenfox [79]

Answer: b) The probability that an item produced by this process is defective is likely to be close to 0.15, but not exactly equal to 0.15.

Step-by-step explanation:

Given that:

Number of samples = 100

Number of defective samples = 15

Proportion =number defective samples / total samples

P = 15 / 100 = 0.15

Hence, the probability that an item produces is defective is 0.15.

However, due to sampling Variations, the probability will be corrected for these variations. Hence, probability that an item produced by this process is defective is likely to be close to 0.15, but not exactly equal to 0.15.

5 0
2 years ago
In △PKQ, PK = KQ = 12, m∠P = 35º. Find PQ.
Neporo4naja [7]

The length of PQ is 19.66 units

Step-by-step explanation:

The given is:

1. PK = KQ = 12

2. m∠P = 35º

We need to find the length pf PQ

∵ PK = KQ

∴ m∠P = m∠Q

∵ m∠P = 35°

∴ m∠Q = 35°

The sum of measures of the angles of a triangle is 180°

∴ m∠P + m∠Q + m∠K = 180°

∴ 35 + 35 + m∠K = 180

∴ 70 + m∠K = 180

- Subtract 70 from both sides

∴ m∠K = 110°

Let us use cosine rule to find the length of PQ

∵ PQ = \sqrt{(KP)^{2}+(KQ)^{2}-2(KP)(KQ)cos(K)}

∵ PK = 12 , KQ = 12 , m∠K = 110°

- Substitute these values in the rule

∴ PQ = \sqrt{(12)^{2}+(12)^{2}-2(12)(12)cos(110)}

∴ PQ = 19.66

The length of PQ is 19.66 units

Learn more:

You can learn more about triangle in brainly.com/question/12985572

#LearnwithBrainly

4 0
3 years ago
How do I solve 2cos(x)=2sin(2x)
Vedmedyk [2.9K]
2cosx=2sin2x. Sin2x is an identity for 2sinxcos. So 2[2sinxcosx] gives you 4sinxcosx. 2cosx=4sinxcosx. Divide 2cosx on both sides and gives you 2sinx=0 and divide again, sinx=0. Sinx is 0 at 0 and 360 degrees, or pi and 2pi. So thats what x would be. 0,360,pi,2pi.
4 0
3 years ago
If f(x) = 2(34) + 1, what is the value of f(2)? <br>​
larisa86 [58]
I believe that f(2) is 34.5

f(2) = 2(34) + 1
f(2) = 68 + 1
f(2) = 69
f = 69/2
f = 34.5

I AM NOT SURE
3 0
2 years ago
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