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Serjik [45]
3 years ago
10

Select the point that is a solution to the system if inequalities yx^2-6

Mathematics
1 answer:
labwork [276]3 years ago
8 0

Answer:

The correct answer is A.

A(0,-2)

Step-by-step explanation:

Method 1

You just have to plot each point on the graph.

The one that falls within the solution region is the correct choice.

From the graph, A(0,-2) falls within the solution region.

See graph

Method 2

If you substitute the points into the inequalities, the only point that will satisfy both inequalities simultaneously is A.

The first inequality is

y\:

If we substitute A(0,-2), we get;

-2\:


-2\:


This statement is true.

The second inequality is

y\:>\:x^2-6

If we substitute A(0,-2), we get;

-2\:>\:(0)^2-6

This gives,

-2\:>\:-6

This statement is also true.



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If cos(2/3x+20)°=sin(2x−10)°, find the acute angles of the corresponding right triangle.
adell [148]

Answer:

A = 40°

B = 50°

Step-by-step explanation:

If cos A = sin B, then A + B = 90

So, 2x/3 + 20  + 2x - 10 = 90

      2x + 60 + 6x - 30 = 270

               8x + 30 = 270

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2x/3 + 20 = 60/3 + 20 = 20 + 20 = 40

2x - 10 = 2(30) - 10 = 60 - 10 = 50  or  90 - 40 = 50

       

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3 years ago
Show all work. <br><br>PLEASE HELP!!!!
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(a) Using the table, give the values fo rthe inverse


1) original table of values:


x      1     2     3    4    5

f(x)   0     1     1    5    3


2) The inverse of the function is obtained by exchanging x and f(x), this is:


                   ( x, f(x) ) → ( f(x), x)


3) So, the table of values of the inverse of the given function is:


x          0    1     1      5     3

f⁻¹ (x)   0     1     2     3     4


(b) Is the inverse a function?


No, the inverse is not a function, since the table of the inverse shows that the x -value 1 has two different images.


This ambigüity is opposite to the definition of a function, which requires that any input value has only one output. For that reason, the inverse is not a function. You cannot tell whether the image of 1 is 1 or 2, because both are images of the same value.
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