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Vitek1552 [10]
2 years ago
10

Im really confused, can someone answer/explain?

Mathematics
1 answer:
natali 33 [55]2 years ago
6 0

Answer:

0<=x<10 or [1,10)

Step-by-step explanation:

You need to solve this using logarithms.  I will use natural logarithms (LN on your calculator)

15,000 is the initial price of the car because 0.88^0=1.

All we need is 0.88^x>0.1

Remember that the logarithm of a^b is b*LN(a).

x*LN(0.88)>LN(0.1)

x<LN(0.1)/LN(0.88)

The relation changes from > to < because we are dividing by LN(0.88) which is negative.

The calculator now yields

LN(0.1)/LN(0.88)=10

So, x<10 years.  But you buy the car at x=0, hence the relevant domain is.

0<=x<10 or [1,10)

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Answer:

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Jim paid 750$ for his new computer. In addition, she paid 63.75 in taxes. What was the tax rate Jim paid on his new car​
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HELP PLS Given a polynomial function f(x), describe the effects on the Y-intercept, regions where the graph is increasing and de
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1. Remarks:

f(x) to f(x)-3 is the whole graph of f(x), shifted 3 units down. 

f(x) to -2f(x): 

The effect of "multiplication by -" is that the whole graph is reflected with respect to the x axis, so it is turned upside down.
 
The effect of "multiplication by 2" is that every point is "stretched vertically by a factor of 2" . So for example the point (-1, -4) in the original function, becomes (-1, -8) in the second one. Or (2, 5) would become (2, 10). 

The only points that do not change (are not streched vertically) are the roots. For example if (4,0) is an x-intercept (a root) in the original function, (4,0) is still a root in the second one because  2 times 0 is still 0.


2. Consider the polynomial function of degree n: 

f(x)= a_{n} x^{n} +a_{n-1} x^{n-1}+....+a_{2} x^{2}+a_{1} x^{1}+a_{0}

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The y - intercept is the value of the polynomial function at x=0. 
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in f(x)-3 the y intercept is shifted 3 units down as any other point, so it becomes  a_{0}-3

In -2f(x), the y-intercept a_{0} becomes -2a_{0}

b. Regions of f decreasing or increasing

f(x)-3 is f(x) just shifted down 3 units, so they are both increasing and decreasing in the same intervals of x

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c. End behaviors

By now it is clear that end behaviors of f(x) and f(x)-3 are same, and f(x) with -2f(x) are opposite

d. Evenness, oddness

If f(x) is even, then f(x)=f(-x)

Let g(x)=f(x)-3

g(x)=f(x)-3=f(-x)-3=g(-3), so in this case f(x)-3 is even

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so -g(x)=f(-x)+3

g(-x)=f(-x)-3,  

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Consider f(x)=-2f(x)

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The conclusions about oddness and evenness can be also derived from the discussions about the graphs.
 

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ANSWER
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EXPLANATION

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