Answer:
![g(x)=\sqrt[3]{x-3}+4](https://tex.z-dn.net/?f=g%28x%29%3D%5Csqrt%5B3%5D%7Bx-3%7D%2B4)
Step-by-step explanation:
The function g(x) is a shifted version of the function f(x); f(x) is shifted by 3 along x-axis and by 4 along y-axis.
Another way of thinking about this is that the function g(x) contains points (3, 4); therefore,
which goes through the point (3, 4).
I think it's the second equation. I could be wrong but I think that's what it is
Answer:
I hope I know but I need help my self
first term = initial number
second term = initial number + common difference
third term = initial number + 2(common difference)
So...
2x+5-(x+4) = common difference
4x+3-(2x+5) = also common difference
2x+5-(x+4) = x+1
4x+3-(2x+5) = 2x-2
Because x+1=2x-2 we can solve for x.
x=3
So the sequence goes... 7,11,15...
19 is the fourth term
(f+g) (x)= f(x) + g(f)
= IxI + 9 + (-6)
= IxI + 9 - 6
= IxI + 3
(f + g)(x) = IxI + 3
