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andre [41]
2 years ago
8

Area of triangle Question 4

Mathematics
1 answer:
Marat540 [252]2 years ago
3 0

Answer:

3sq units

Step-by-step explanation:

bxh = 2x3=6

6/2=3

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The owner of a motel has 2900 m of fencing and wants to enclose a rectangular plot of land that borders a straight highway. If s
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Answer:

Step-by-step explanation:

Given that the owner of a motel has 2900 m of fencing and wants to enclose a rectangular plot of land that borders a straight highway.

Fencing is used for 2times length and 1 width if highway side is taken as width

So we have 2l+w = 2900

Or w = 2900-2l

Area of the rectangular region = lw

A(l) = l(2900-2l) = 2900l-2l^2\\

Use derivative test to find the maximum

A'(l) = 2900-4l\\A"(l) = -4

So maximum when I derivative =0

i.e when l =\frac{2900}{4} =725

Largest area = A(725)

= 725(2900-2*725)\\= 1051250

1051250 sqm is area maximum

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Which of the following statements is not always true? A. In a rhombus, both pairs of opposite sides are parallel. B. In a rhombu
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Answer:

Step-by-step explanation:

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Suppose that 10% of the undergraduates at a certain university are foreign students, and that 25% of the graduate students are f
Deffense [45]

Answer:

0.6154 = 61.54% probability that the student is an undergraduate

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Foreign

Event B: Undergraduate.

There are four times as many undergraduates as graduate students

So 4/5 = 80% are undergraduate students and 1/5 = 20% are graduate students.

Probability the student is foreign:

10% of 80%

25% of 20%. So

P(A) = 0.1*0.8 + 0.25*0.2 = 0.13

Probability that a student is foreign and undergraduate:

10% of 80%. So

P(A \cap B) = 0.1*0.8 = 0.08

What is the probability that the student is an undergraduate?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.08}{0.13} = 0.6154

0.6154 = 61.54% probability that the student is an undergraduate

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3 years ago
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