Answer:
12
Step-by-step explanation:
Using the pythagorean theorem, we know that a^2+ b^2=c^2
In our case, we know b, which is 5 and c which is 13.
If we plug that into the equation, we get a^2+ 5^2 = 13^2
Next, we simplify the equation. a^2 + 25 = 169
Then we subtract 25 from 169. 169 - 25 = 144.
Lastly, we do the square root of 144 and we get 12 which is the missing side.
Answer:
340
Step-by-step explanation:
10 ×16=160
12×15=180
160+180=340 so a total of 340 calendars
Answer: see proof below
<u>Step-by-step explanation:</u>
Given: A + B + C = π → C = π - (A + B)
→ sin C = sin(π - (A + B)) cos C = sin(π - (A + B))
→ sin C = sin (A + B) cos C = - cos(A + B)
Use the following Sum to Product Identity:
sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]
cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]
Use the following Double Angle Identity:
sin 2A = 2 sin A · cos A
<u>Proof LHS → RHS</u>
LHS: (sin 2A + sin 2B) + sin 2C




![\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]](https://tex.z-dn.net/?f=%5Ctext%7BFactor%3A%7D%5Cqquad%20%5Cqquad%20%5Cqquad%202%5Csin%20C%5Ccdot%20%5B%5Ccos%20%28A-B%29%2B%5Ccos%20%28A%2BB%29%5D)


LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C 
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