The end behavior of the graph of f(x) = -0.25x2 - 2x + 1 is that A) As x increases, f(x) increases. As x decreases, f(x) decreases.
<h3>What is the end behavior about?</h3>The end behavior of a function f tells us that the way that the graph function behaves at the "ends" of the x-axis.
Note that the end behavior of a function tells the trend of the graph and in this graph, f(x) -----> +∞ as x----> -∞ (as the value of x decreases the value of f(x) increases) and f(x) -----> -∞ as x----> +∞ (as the value of x increases the value of f(x) decreases).
Therefore, The end behavior of the graph of f(x) = -0.25x2 - 2x + 1 is that A) As x increases, f(x) increases. As x decreases, f(x) decreases.
See full question below
What is the end behavior of the graph of f(x) = -0.25x2 - 2x + 1?
A) As x increases, f(x) increases. As x decreases, f(x) decreases.
B) As x increases, f(x) decreases. As x decreases, f(x) decreases.
C) As x increases, f(x) increases. As x decreases, f(x) increases.
D) As x increases, f(x) decreases. As x decreases, f(x) increases
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Answer:
Step-by-step explanation:
we have
This is the equation of a vertical parabola open upward
The vertex is a minimum
The equation of a vertical parabola in vertex form is equal to
where
(h,k) is the vertex
Convert the given function to vertex form
Factor the leading coefficient
Complete the square
Rewrite as perfect squares
------> equation in vertex form
The vertex is the point (2,6)