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3 years ago

In the given figure, which angle is complementary to <4

Mathematics

1 answer:

Ugo [173]3 years ago

6 0

Answer: The definition of a complementary angle is "Either of two angles whose sum is 90°." Thus the complementary angle for 4 is angle 5.

P.S. if you feel this answer is satisfactory I would appreciate it if you would mark it brainiest.

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Graph the function

Oksana_A [137]

Answer:

To graph a rational function, you find the asymptotes and the intercepts, plot a few points, and then ... graphing showing vertical asymptote at x = 1 ... Next, I'll find any x- or y- intercepts.

6 0

3 years ago

Dan has already delivered 48 donuts today. For the next few hours, Dan will deliver 60 donuts per hour. Match the number of donu

frez [133]

A.number of donuts delivered 2 hours from now.
2. Next=now +60+60
starting at 48 because 2 hours meant 2*60 = 60+60

B. number of donuts delivered 7 hours from now C
3.Next= now +420
starting at 48 because 7 hours meant 7*60 = 420 mn

C.number of donuts delivered n hours from now.
4. Next=now+60n
starting at 48 (this is obvious)

so finally,
D. number of donuts delivered 6 hours from now.
1. Next= now+ 6*60
starting at 48

7 0

3 years ago

Evaluate. Write your answer in simplified, rationalized form. Do not round.

borishaifa [10]

Answer:

cos(45°) = (√2)/2

Step-by-step explanation:

The cosine of 45° is the x-coordinate of the point on the unit circle where the line y=x intersects it. That is, it is the positive solution to the equation ...

x^2 +x^2 = 1

x^2 = 1/2 = 2/4 . . . . . collect terms, divide by 2, express the fraction with a square denominator

x = √(2/4) . . . . . . take the square root

x = (√2)/2 . . . . . simplify

The cosine of 45° is (√2)/2.

3 0

2 years ago

On a scale drawing , a tree is 6 3/4 inches tall.The scale factor is 1/20 . Find the height of the actual tree.

Crank

Answer:

Step-by-step explanation: ⣠⠤⠖⠚⢉⣩⣭⡭⠛⠓⠲⠦⣄⡀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⢀⡴⠋⠁⠀⠀⠊⠀⠀⠀⠀⠀⠀⠀⠀⠀⠉⠳⢦⡀⠀⠀⠀⠀

⠀⠀⠀⠀⢀⡴⠃⢀⡴⢳⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠙⣆⠀⠀⠀

⠀⠀⠀⠀⡾⠁⣠⠋⠀⠈⢧⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠈⢧⠀⠀

⠀⠀⠀⣸⠁⢰⠃⠀⠀⠀⠈⢣⡀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠈⣇⠀

⠀⠀⠀⡇⠀⡾⡀⠀⠀⠀⠀⣀⣹⣆⡀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢹⠀

⠀⠀⢸⠃⢀⣇⡈⠀⠀⠀⠀⠀⠀⢀⡑⢄⡀⢀⡀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢸⡇

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⡇⠀⡇⠀⠀⡀⠀⡴⠋⠀⠀⠀⠀⠀⠀⠀⠸⡌⣵⡀⢳⡇⠀⠀⠀⠀⠀⠀⢹⡀

⡇⠀⠇⠀⠀⡇⡸⠁⠀⠀⠀⠀⠀⠀⠀⠀⠀⠙⠮⢧⣀⣻⢂⠀⠀⠀⠀⠀⠀⢧

⣇⠀⢠⠀⠀⢳⠇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠈⡎⣆⠀⠀⠀⠀⠀⠘

⢻⠀⠈⠰⠀⢸⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠰⠘⢮⣧⡀⠀⠀⠀⠀

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3 years ago

write a polynomial function of least degree with integral coefficients that has the given zeros. -(1/3), -i

inessss [21]

Answer:

$f(x)=3x^3+x^2+3x+1$

Step-by-step explanation:

If a real number $-\frac{1}{3}$ is a zero of polynomial function, then

$x-\left(-\dfrac{1}{3}\right)=x+\dfrac{1}{3}$

is the factor of this function.

If a complex number $-i$ is a xero of the polynomial function, then the complex number $i$ is also a zero of this function and

$x-(-i)=x+i\ \text{ and }\ x-i$

are two factors of this function.

So, the function of least degree is

$f(x)=\left(x+\dfrac{1}{3}\right)(x+i)(x-i)=\left(x+\dfrac{1}{3}\right)(x^2-i^2)=\\ \\ =\left(x+\dfrac{1}{3}\right)(x^2+1)=\dfrac{1}{3}(3x+1)(x^2+1)=\dfrac{1}{3}(3x^3+x^2+3x+1)$

If the polynomial function must be with integer coefficients, then it has a form

$f(x)=3x^3+x^2+3x+1$

4 0

4 years ago