<span>Step 1: 0.46 = 46⁄100</span>
<span>Step 2: Simplify 46⁄100 = 23⁄50</span><span> hope this helped u</span>
The speed of slower bus is 118 km/hr and speed of faster bus is 133 km/hr
<h3>What is speed?</h3>
Speed is a scalar quantity that refers to "how fast an object is moving".
Given that, two buses leave a station at the same time and travel in opposite directions, one bus travels 15 km/h faster than the other, the two buses are 1004 kilometres apart after 4 hours,
Speed = distance/ time
Let the speed of the slower bus be v and the faster bus be (v+15)
According to the question,
vt + (v+15)t = 1004
vt + vt + 15t = 1004
t = 4
4v + 4v + 60 = 1004
8v = 944
v = 118
Hence, The speed of slower bus is 118 km/hr and speed of faster bus is 133 km/hr
For more references on speed, click;
brainly.com/question/7359669
#SPJ1
3 = 3/4(b - 8)
Switch sides
3/4(b - 8) = 3
Next, multiply both sides by 4
4 * 3/4(b - 8) = 3 * 4
Then simplify,
3(b - 8) = 12
Next, divide both sides by 3
3(b - 8)/3 = 12/3
Then, simplify
b - 8 = 4
Then, add 8 to both sides
b - 8 + 8 = 4 + 8
Simplify, b = 12
Answer:
5:11
Step-by-step explanation:
