All categories

3 years ago

What is the greatest common factor of 49 and 84? 3 4 7 9

Mathematics

2 answers:

cluponka [151]3 years ago

7 0

The answer is 7 since neither 49 nor 84 are divisible by 9

bonufazy [111]3 years ago

6 0

49: 1 7, 49
84: 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84

The GCF is 7

You might be interested in

City A had a population of 10000 in the year 1990. City A’s population grows at a constant rate of 3% per year. City B has a pop

Georgia [21]

Answer:

City A and city B will have equal population 25years after 1990

Step-by-step explanation:

Given

Let

$t \to$ years after 1990

$A_t \to$ population function of city A

$B_t \to$ population function of city B

City A

$A_0 = 10000$ ---- initial population (1990)

$r_A =3\%$ --- rate

City B

$B_{10} = \frac{1}{2} * A_{10}$ ----- t = 10 in 2000

$A_{20} = B_{20} * (1 + 20\%)$ ---- t = 20 in 2010

Required

When they will have the same population

Both functions follow exponential function.

So, we have:

$A_t = A_0 * (1 + r_A)^t$

$B_t = B_0 * (1 + r_B)^t$

Calculate the population of city A in 2000 (t = 10)

$A_t = A_0 * (1 + r_A)^t$

$A_{10} = 10000 * (1 + 3\%)^{10}$

$A_{10} = 10000 * (1 + 0.03)^{10}$

$A_{10} = 10000 * (1.03)^{10}$

$A_{10} = 13439.16$

Calculate the population of city A in 2010 (t = 20)

$A_t = A_0 * (1 + r_A)^t$

$A_{20} = 10000 * (1 + 3\%)^{20}$

$A_{20} = 10000 * (1 + 0.03)^{20}$

$A_{20} = 10000 * (1.03)^{20}$

$A_{20} = 18061.11$

From the question, we have:

$B_{10} = \frac{1}{2} * A_{10}$ and $A_{20} = B_{20} * (1 + 20\%)$

$B_{10} = \frac{1}{2} * A_{10}$

$B_{10} = \frac{1}{2} * 13439.16$

$B_{10} = 6719.58$

$A_{20} = B_{20} * (1 + 20\%)$

$18061.11 = B_{20} * (1 + 20\%)$

$18061.11 = B_{20} * (1 + 0.20)$

$18061.11 = B_{20} * (1.20)$

Solve for B20

$B_{20} = \frac{18061.11}{1.20}$

$B_{20} = 15050.93$

$B_{10} = 6719.58$ and $B_{20} = 15050.93$ can be used to determine the function of city B

$B_t = B_0 * (1 + r_B)^t$

For: $B_{10} = 6719.58$

We have:

$B_{10} = B_0 * (1 + r_B)^{10}$

$B_0 * (1 + r_B)^{10} = 6719.58$

For: $B_{20} = 15050.93$

We have:

$B_{20} = B_0 * (1 + r_B)^{20}$

$B_0 * (1 + r_B)^{20} = 15050.93$

Divide $B_0 * (1 + r_B)^{20} = 15050.93$ by $B_0 * (1 + r_B)^{10} = 6719.58$

$\frac{B_0 * (1 + r_B)^{20}}{B_0 * (1 + r_B)^{10}} = \frac{15050.93}{6719.58}$

$\frac{(1 + r_B)^{20}}{(1 + r_B)^{10}} = 2.2399$

Apply law of indices

$(1 + r_B)^{20-10} = 2.2399$

$(1 + r_B)^{10} = 2.2399$ --- (1)

Take 10th root of both sides

$1 + r_B = \sqrt[10]{2.2399}$

$1 + r_B = 1.08$

Subtract 1 from both sides

$r_B = 0.08$

To calculate $B_0$ , we have:

$B_0 * (1 + r_B)^{10} = 6719.58$

Recall that: $(1 + r_B)^{10} = 2.2399$

So:

$B_0 * 2.2399 = 6719.58$

$B_0 = \frac{6719.58}{2.2399}$

$B_0 = 3000$

Hence:

$B_t = B_0 * (1 + r_B)^t$

$B_t = 3000 * (1 + 0.08)^t$

$B_t = 3000 * (1.08)^t$

The question requires that we solve for t when:

$A_t = B_t$

Where:

$A_t = A_0 * (1 + r_A)^t$

$A_t = 10000 * (1 + 3\%)^t$

$A_t = 10000 * (1 + 0.03)^t$

$A_t = 10000 * (1.03)^t$

and

$B_t = 3000 * (1.08)^t$

$A_t = B_t$ becomes

$10000 * (1.03)^t = 3000 * (1.08)^t$

Divide both sides by 10000

$(1.03)^t = 0.3 * (1.08)^t$

Divide both sides by $(1.08)^t$

$(\frac{1.03}{1.08})^t = 0.3$

$(0.9537)^t = 0.3$

Take natural logarithm of both sides

$\ln(0.9537)^t = \ln(0.3)$

Rewrite as:

$t\cdot\ln(0.9537) = \ln(0.3)$

Solve for t

$t = \frac{\ln(0.3)}{ln(0.9537)}$

$t = 25.397$

Approximate

$t = 25$

7 0

3 years ago

HELP QUICK will mark brainliest

slamgirl [31]

Answer:

Step-by-step explanation:

(5x4) - 6 / 2 = x

7 0

3 years ago

Read 2 more answers

Which quiz did met have a better score?

MaRussiya [10]

I'm her first quiz she did better, this is going to be hard to explain but pay attention 92% as a decimal is 92/100 keep this in mind, then 27 out of 30 question we try to make 30 go into 100 but we know 30 can't go into 100 without a decimal so what we do is we change the decimal to 90 so for the 27 out of 30 it is now 81/90, now we need to change the denominator in 92/100 to 90 so we subtract 10 from the numerator and denominator to get 82/100 so compare the 2 decimals you got 81/90 and 82/90 and you find that 82/90 is bigger so she did better on the first quiz

7 0

3 years ago

Read 2 more answers

The grocery store is located at a point on a coordinate plane with the same y-coordinate as the bank but with the opposite x-coo

Alexxandr [17]

Across the y axis. This question becomes easier if you graph it out in your head. Let's say the bank is at (2,2). Because the grocery store has an opposite x coordinate, the bank would be at (-2,2). If you look at this in your head, they are not even on different sides of the x axis, and therefore must be reflected across the y axis.

4 0

3 years ago

Read 2 more answers

Write 43 as a sum of powers of 2. (2 Has to be the Base not the exponent)

slamgirl [31]

Answer:

2⁰ + 2¹+ 2⁵ +2³ = 43

Step-by-step explanation:

since 43 is odd, we know 2⁰ or 1 must be one of the sums

43 - 2⁰ = 42

42 - 2¹ = 40

16 = 2⁴

40-2(16) = 40 - 2⁵ = 8

8 = 2³

adding this all together

2⁰ + 2¹+ 2⁵ +2³ = 43

6 0

3 years ago