Answer:
The critical region for α= 0.05 is Z > ± 1.645
The calculated value of Z= 1.100
Step-by-step explanation:
The null and alternate hypotheses are given
H0: μ ≤ 43
H1: μ > 43 one tail test
∝= 0.05
n= 29
Standard Deviation= s= 4.1
Mean = μ0 = 44
For one tail test the z value of α= ± 1.645
The critical region for α= 0.05 is Z > ± 1.645
The test statistic is given by
z=μ0-μ/ s/√n
Z= 44-43/4.1/√29
Z= 1/4.1/√29
Z= 1.100
Since the calculated value Z= 1.100 does not fall in the critical region , We reject H0 and may conclude that the mean number of calls per salesperson per week is not more than 43
The formula you can use for the withdrawals is that of an annuity. You have interest adding to the balance at the same time withdrawals are reducing the balance.
The formula I remember for annuities is
.. A = Pi/(1 -(1 +i)^-n) . . . . . i is the interest for each of the n intervals; A is the withdrawal, P is the initial balance.
This formula works when the withdrawal is at the end of the interval. To find the principal amount required at the time of the first withdrawal, we will compute for 3 withdrawals and then add the 7500 amount of the first withdrawal.
.. 7500 = P*.036/(1 -1.036^-3)
.. 7500 = P*0.357616
.. 7500/0.0347616 = P = 20,972.20
so the college fund balance in 4 years needs to be
.. 20,972.20 +7,500 = 28,472.20
Since the last payment P into the college fund earns interest, its value at the time of the first withdrawal is P*1.036. Each deposit before that earns a year's interest, so the balance in the fund after 4 deposits is
.. B = P*1.036*(1.036^4 -1)/(1.036 -1)
We want this balance to be the above amount, so the deposit (P) is
.. 28,472.20*0.036/(1.036*(1.036^4 -1)) = 6510.62
You must make 4 annual deposits of $6,510.62 starting now.
Y= 3/6 x - 3
or
y= 1/2 x -3
