Ask question

Ask question

All categories

3 years ago

5

Marcy bought 10.32 pounds of white potatoes and 12.48 pounds of sweet potatoes. About how many pounds of potatoes did Marcy buy?

Round each weight to the nearest tenth to estimate the total weight of potatoes that Marcy bought.

1 answer:

zalisa [80]3 years ago

3 0

Marcy bought a total of 22.8 potatoes. 10.32+12.48=22.8

You might be interested in

Mary's SUV has a 15-gallon gas tank. The SUV gets an estimated 24 miles per gallon.

Delvig [45]

Answer:

A = 360

B= 180

C=270

Step-by-step explanation:

5 0

3 years ago

A 20-sided regular polygon has an angle measure represented as 3gº.

Andre45 [30]

The value of g in the 20 sided regular polygon is 54.

<h3>How to find the angles of a regular polygon?</h3>

If all the polygon sides and interior angles are equal, then they are known as regular polygons.

The polygon given is a 20 sided regular polygon and the measure of each angle is 3g degrees.

Therefore, let's find g.

The sum of interior angles of a 20 sided polygon is as follows:

180(n - 2) = 180(20 - 2) = 180(18) = 3240

Therefore,

each angle = 3240 / 20 = 162

Hence,

162 = 3g

g = 162 / 3

Therefore,

g = 54

learn more on regular polygon here: brainly.com/question/16992545

#SPJ1

8 0

1 year ago

Find the volume of the following solid. The solid between the cylinder f(x,y)equals=e Superscript negative xe−x and the region

PilotLPTM [1.2K]

It is hard to comprehend your question. As far as I understand:

f(x,y) = e^(-x)

Find the volume over region R = {(x,y): 0<=x<=ln(6), -6<=y <= 6}.

That is all I understood. It would be easier to understand with a picture or some kind of visual aid.

Anyways, to find the volume between the surface and your rectangular region R, we must evaluate a double integral of f on the region R.

$\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy$

Now evaluate,

$\int_{0}^{ln(6)}e^{-x}dx$

which evaluates to, 5/6 if I did the math correct. Correct me if I am wrong.

Now integrate this w.r.t. y:

$\int_{-6}^{6}\frac{5}{6}dy = 10$

So,

$\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy = 10$

7 0

3 years ago

Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

7 0

3 years ago

Michael has 3 quarters, 2 dimes, and 3 nickels in his pocket. He randomly draws two coins from his pocket, one at a time, and th

salantis [7]

Answer:

No. Choosing two dimes are dependent events. The probability of choosing the first dime is 1/4 and the probability of choosing the second dime is 1/7 . The probability that both coins are dimes is

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers