<em>The answer is Ms Hernandez can bring up to 6 people to the zoo.</em>
<em />
<em>x - the number of people that she can bring to the zoo</em>
<em>The parking will cost $7: a = 7</em>
<em>Admission tickets will cost $15.50 per person: b = 15.50x</em>
<em>She can spend on parking and admission tickets $100:</em>
a + b ≤ 100
a = 7
b = 15.50x
7 + 15.50x ≤ 100
15.50x ≤ 100 - 7
15.50x ≤ 93
x ≤ 93 / 15.50
x ≤ 6
Answer:
it would be 2
Step-by-step explanation:
Answer:
25, 29
Step-by-step explanation:
The Pythagorean Theorem is a² + b² = c² where a and b are legs and c is the hypotenuse. In this case, a = 2, b = 5 and we are solving for c, which is also known as AC here. Therefore,
4 + 25 = AC²
AC² = 29
The average rate of change of a graph between two intervals is given by the difference in value of the values on the graph of the two interval divided by the difference between the two intervals.
Part A.
From the graph the average Valentine's day spending in 2005 is 98 while the average Valentine's day spending in 2007 is 120.
The average rate of change in spending between 2005 and 2007 is given by

Part B
From the graph the average Valentine's day spending in 2004 is 100 while the average Valentine's day spending in 2010 is 103.
The average rate of change in spending between 2004 and 2010 is given by

Part C:
From the graph the average Valentine's day spending in 2009 is 102 while the average Valentine's day spending in 2010 is 103.
The average rate of change in spending between 2009 and 2010 is given by