Answers:
Vertex is (-1,0)
Axis of symmetry is x = -1
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Explanation:
F(x) = 3(x+1)^2
is the same as
y = 3(x-(-1))^2 + 0
which is in the form
y = a(x-h)^2 + k
We can see that
a = 3
h = -1
k = 0
Therefore the vertex is (h,k) = (-1,0)
The axis of symmetry is x = h = -1 which is the equation x = -1
The axis of symmetry in this case is a vertical line through the vertex.
Hello :)
(A)If we want to find a, we can F/m=a
(B) F=m.a
F=10.a
F/10 = a
(C) = F=m.a
25=m.5
m= 25/5
m= 5
Have a nice day :)
Problem 1
We're given that angle A = angle B. Also that angle B = angle C.
By the transitive property, we can say angle A = angle C.
So basically all three angles are equal to one another. Let's call that unknown angle x.
For any triangle, the three angles always add to 180, so,
x+x+x = 180
3x = 180
x = 180/3
x = 60
That proves angles A,B, and C are each 60 degrees. This triangle is considered equiangular since all angles are the same. Furthermore, the triangle is also considered equilateral meaning all sides are the same. The term equilateral is more widely used, so I'd go with that term if you could only pick one.
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Problem 2
As mentioned in problem 1, the three angles of a triangle add to 180
A+B+C = 180
A+B+90 = 180
A+B+90-90 = 180-90
A+B = 90
This shows A and B are complementary angles. Complementary angles by definition add to 90 degrees.
56/.04=1400
Is that what you meant?
Answer:
The correct answer is option A.
Step-by-step explanation:
Given : line AB intersect CD at P. PR is perpendicular to AB.
∠APD = 170°
To find = ∠DPB =?
Solution :
line AB intersect CD at P:
So,∠APD =∠BPC = 170° ..[1]
(vertically opposite angles of two straight lines intersecting at common point are equal)
On line CD two angles are ∠BPC ,∠DPB
∠BPC + ∠DPB =180° (supplementary angles)
170°+ ∠DPB =180°
∠DPB =180° - 170° = 10°
So, the measure of ∠DPB is 10°.
