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Scrat [10]
3 years ago
15

!!!!!!!WILL MARK BRAINLIEST!!!!!!!!!A sudden increase in activity level can cause stress fractures.

Biology
1 answer:
anyanavicka [17]3 years ago
6 0

Answer:

Its True

Explanation:

This is called bone stress. This can develop into a stress fracture if the level of load bearing/activity is not reduced. Stress fractures commonly occur when there is a sudden change in physical activity or increase in training without enough rest time for the bone to adapt and remodel.

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The species of tree shown below grows in a wide range of temperatures in a desert area in Africa, where average temperatures hav
Marina CMI [18]

Answer:

Explanation:b

4 0
2 years ago
On the pH scale, acids fall between ____ and bases fall between
skelet666 [1.2K]

Answer:

The correct answer is - O and 6.9; 7.1 and 14

Explanation:

A measuring scale that tells about the acidity or basicity or alkaline nature of a particular object or solution is possible with the help of a pH scale that measures how acidic or basic a solution or object is.

It ranges between 0 to 14. pH less than 7 or ranging from 0.0 to 6.9 is acidic and more than 7 or from 7.1 to 14.0 is basic or alkaline in nature. A measure of the relative amount of H+ ion and OH- ions in water is pH.

3 0
3 years ago
small group of 100 people decide to isolate themselves from the world and move to a small and remote deserted island. Out of thi
irina [24]

Answer:

Frequency of p = 0.684

Frequency of p = 0.316

Number of individuals with homozygous dominant (AA) = 47

Number of individuals with heterozygous (Aa)= 43

Number of individuals with homozygous recessive (aa) = 10

Explanation:

Out of 100 people, 10 have albino skin (aa)

So, the frequency of homozygous recessive individuals (q^{2}) is \frac{10}{100} = 0.1

Now, q will be

= \sqrt{q^{2} } = \sqrt{0.1} \\= 0.316

As per Hardy Weinberg's equation -

p + q = 1

Substituting the value of q in above equation, we get -

p + 0.316 = 1p = 1 -0.316\\p = 0.684

Now the frequency of homozygous dominant (AA) will be

p^{2} = 0.684^{2} \\= 0.467

Hence, out of 100 people 0.467 * 100 = 46.7 or 47 people are homozygous dominant (AA)

Like wise out of 100 people 0.1 * 100 = 10 people are homozygous recessive (aa)

As per As per Hardy Weinberg's equation-

p^{2} + q^{2} + 2pq = 1\\

Substituting the values in above equation, we get -

0.467 + 0.316 + 2pq = 1\\2pq = 1 -( 0.467+ 0.1)\\2pq = 0.433

So, out of 100 people 0.433 * 100 = 43.3 or 43 people are heterozygous (Aa)

7 0
3 years ago
Can someone please Help me and dont delet it
jeka57 [31]

Answer:srry, i dont know the answer

4 0
3 years ago
Does anyone know the answers to this
GarryVolchara [31]

Answer:

try asking Goo I know she would help

7 0
3 years ago
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