Answer:
The probability of founding exactly one defective item in the sample is P=0.275.
The mean and variance of defective components in the sample are:
![\mu=0.375\\\\\sigma^2=0.347](https://tex.z-dn.net/?f=%5Cmu%3D0.375%5C%5C%5C%5C%5Csigma%5E2%3D0.347)
Step-by-step explanation:
In the case we have a lot with 3 defectives components, the proportion of defectives is:
![p=3/40=0.075](https://tex.z-dn.net/?f=p%3D3%2F40%3D0.075)
a) The number of defectives components in the 5-components sample will follow a binomial distribution B(5,0.075).
The probability of having one defective in the sample is:
![P(k=5)=\binom{5}{1}p^1(1-p)^4=5*0.075*0.925^4=0.275](https://tex.z-dn.net/?f=P%28k%3D5%29%3D%5Cbinom%7B5%7D%7B1%7Dp%5E1%281-p%29%5E4%3D5%2A0.075%2A0.925%5E4%3D0.275)
b) The mean and variance of defective components in the sample is:
![\mu=np=5*0.075=0.375\\\\\sigma^2=npq=5*0.075*0.925=0.347](https://tex.z-dn.net/?f=%5Cmu%3Dnp%3D5%2A0.075%3D0.375%5C%5C%5C%5C%5Csigma%5E2%3Dnpq%3D5%2A0.075%2A0.925%3D0.347)
The Chebyschev's inequality established:
![P(|X-\mu|\geq k\sigma)\leq \frac{1}{k^2}](https://tex.z-dn.net/?f=P%28%7CX-%5Cmu%7C%5Cgeq%20k%5Csigma%29%5Cleq%20%5Cfrac%7B1%7D%7Bk%5E2%7D)
Answer and Step-by-step explanation:
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1. Let's write out the equation to subtract.
7t - 2u - 3v - (t - 3v)
Distribute the negative to the t and -3v.
7t - 2u - 3v - t + 3v (The negatives cancel out)
Now simplify by combining like terms.
6t - 2u
This is the answer because the 3v and -3v cancel out.
2. I don't really understand what this is saying. Is there answer choices for this? But what I think its saying is that the lift has a constant of 2.
3. To find out the amount of terms, we would simplify the equation.
2x + 3y - 5x + yz - x
-4x + 3y + yx
Here, we can see that we have 3 terms in this expression.
-4x is the first term, +3y is the second term, and +yx is the third term.
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#teamtrees #WAP (Water And Plant)
Answer:
B
Step-by-step explanation:
4n/4n-4 × n-1/n+1
= 4n(n-1)/(4n-4)(n+1)
= (4n^2 - 4n)/(4n^2 + 4n - 4n-4)
= (4n^2 - 4n)/(4n^2 - 4)
= 4(n^2 - n)/4(n^2 - 1)
=(n^2 - n)/(n^2 - 1)
Answer:
13 is Prime
Step-by-step explanation: