Convert <span>6\frac{3}{8}<span>6<span><span>8</span><span>3</span><span></span></span></span></span><span> to improper fraction. Use this rule: </span><span>a \frac{b}{c}=\frac{ac+b}{c}<span>a<span><span>c</span><span>b</span><span></span></span>=<span><span>c</span><span><span>ac+b</span></span>:</span></span></span>
∣8<span><span><span><span>6×8+3</span></span><span></span></span>−2∣+∣−8<span><span>8</span><span>5</span><span></span></span>−1<span>∣
</span></span>Simplify <span>6\times 8<span>6×8</span></span><span> to </span>48: <span><span><span><span><span>
</span>8</span><span><span>48+3</span></span><span></span></span>−2∣+∣−8<span><span>8</span><span>5</span><span></span></span>−1∣
</span>Simplify <span>48+3<span>48+3</span></span><span> to </span>51:</span><span><span><span><span><span>
</span>8</span><span><span>51</span></span><span></span></span>−2∣+∣−8<span><span>8</span><span>5</span><span></span></span>−1∣
</span> Make the denominators the same:
<span><span><span>51</span><span>/8</span></span>−2×<span><span>8</span><span>8</span><span>
</span></span></span><span>Simplify. Denominators are now the same:
</span>
<span><span><span>51</span><span>/8</span></span>−<span><span>8</span><span><span>16</span></span><span>
</span>
</span></span>Join the denominators: \frac{51-16}{8}<span><span>8</span><span><span>51−16</span></span><span>
</span>
etc.. and your answer will be 14
</span></span>
Answer:
Positive
Step-by-step explanation:
If you multiply both negative, it will always result to positive.
Rule:
+ × + = +
+ × - = -
- × + = -
- × - = +
Answer:
the answer is $2,883$
Step-by-step explanation:
Square.
A square is a rectangle, so rectangle.
A rectangle is a parallelogram, so parallelogram.
Equilateral.
Also Rhombus.
(I think there may be others but these are the few I know)
This procedure is known as estimating or rounding, where one compares the digit to the right is the number and sees whether or not is found within a given range, greater than 5 and can be used to increase the number in question, by a value of 1.
