Tell whether (1,10) is a solution of y>5+6x

Mathematics

2 answers:

laila [671]3 years ago

7 0

Yes just plug in x and y so yes

liraira [26]3 years ago

5 0

y > 5 + 6*x

10 > 5 + 6*1 .... replace x with 1, replace y with 10

10 > 5 + 6

10 > 11 ... this is a false statement because 10 is smaller than 11

Since the last statement is false, this means the first inequality is false when (x,y) = (1,10)

The given point is <u>not</u> a solution

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The function f(x) is given by the set of ordered pairs.

Lana71 [14]

The equation that is true and one that matches the set of ordered pairs of functions is option C. f (0) = 6

<h3>What is the equation about?</h3>

Note that a function can be made to be a given set of ordered pairs such as the ordered pairs (2,4), (3,5), (4,6) can have input functions of (as domain) 2,3,4 and output functions of (as range) of 4,5,6.

So when you see the ordered pairs. {(1,0), (–10,2), (0,6), (3,17), (–2, –1)} one can see that the option that matches to the set of ordered pairs of functions above is f (0) = 6 value x = 0, f (x) = y = 6, ordered pairs (0.6)

See full question below

The function f (x) is given by the set of ordered pairs. {(1,0), (–10,2), (0,6), (3,17), (–2, –1)}:Which equation is true?

f(-10)=1

f(2)=-10

f(0)=6

f(1)=-10

The answer choices are :

f (-10) = 1 values x = -10, f (x) = y = 1, ordered pairs (-10,1)

f (2) = - 10 values x = 2, f (x) = y = -10, ordered pairs (2, -10)

f (0) = 6 value x = 0, f (x) = y = 6, ordered pairs (0.6)

f (1) = - 10 values x = 1, f (x) = y = -10, ordered pairs (1, -10)

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The answer would be c

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