The rate at which the ice changes is -3/8 lb per hr
<h3>What is the rate the ice changes?</h3>
The given parameters are:
Changes =1 3/4 lb to 1/4 lb
Time = 1/4 hr.
The rate the ice changes is calculated as:
Rate = Change/Time
So, we have
Rate = (1/4 lb - 1 3/4 lb)/(1/4 hr)
Evaluate the difference
Rate = (-1 1/2 lb)/(1/4 hr)
Evaluate the quotient
Rate = -3/8 lb per hr
Hence, the rate at which the ice changes is -3/8 lb per hr
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Answer:
∠SRQ = 75º, ∠TQR = 75º, ∠TSR = 105º, ∠STQ = 105º
Step-by-step explanation:
Since the quadrilaterals are similar, their corresponding angles are the same.
Answer:5
Step-by-step explanation:
reverse the steps
2(x+1)/3=4
2(x+1)/3×3=4×3
2(x+1)/2=12/2
x+1=6
x=6-1
x=5
Answer:
BC=√7
Step-by-step explanation:
AC=4
AC=AH+HC
=3HC+HC
=4HC
HC=1/4AC=1/4×4=1
AH=3HC=3×1=3
BH⊥ AC
AB=AC=4

Answer:
Step-by-step explanation:
the answer is 270
hope this helps