Can anyone help me with this

Mathematics

1 answer:

Arte-miy333 [17]2 years ago

4 0

Answer:

No ....................

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Anit [1.1K]

Well the area of a trapezoid is defined by the following formula:
A = $\frac{1}{2}(b_{1} + b_{2})h$ where b₁ and b₂ are the bases of the trapezoid and h is the height of the trapezoid.

Let's plug in what we know into this formula:
h = 7 the perpendicular distance between the two bases
b₁ = 15 the shorter parallel side
b₂ = 25 the longer parallel side made up of 4 + 15 + 6
so, A = $\frac{1}{2} (15+25)(7)=140$

This is in square units of measure of course, so 140 in²

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3 years ago

Which of the following is true for this table?<br><br> Will give brainliest for correct answer.

marshall27 [118]

It could be seen from the table that when x is 2, the y value is 0. Thus, it can be concluded that the x intercept is (2,0)

The correct answer is B

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2 years ago

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Over [174]

Answer: $\bold{\dfrac{4\pm \sqrt{6}}{2}}$

<u>Step-by-step explanation:</u>

$\dfrac{3}{y-2}-2=\dfrac{1}{y-1}\\\\\\\text{Multiply by the LCD (y-2)(y-1) to clear the denominator:}\\\\\dfrac{3}{y-2}(y-2)(y-1)-2(y-2)(y-1)=\dfrac{1}{y-1}(y-2)(y-1)\\\\\\3(y-1)-2(y-2)(y-1)=1(y-2)\\\\3y-3-2(y^2-3y+2)=y-2\\\\3y-3-2y^2+6y-4=y-2\\\\-2y^2+9y-7=y-2\\\\0=2y^2-8y+5\quad \rightarrow \quad a=2,\ b=-8,\ c=5\\\\\\\text{Quadratic formula is: }x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(-8)\pm \sqrt{(-8)^2-4(2)(5)}}{2(2)}\\\\\\.\ =\dfrac{8\pm \sqrt{64-40}}{2(2)}$

$.\ =\dfrac{8\pm \sqrt{24}}{2(2)}\\\\\\.\ =\dfrac{8\pm 2\sqrt{6}}{2(2)}\\\\\\.\ =\dfrac{4\pm \sqrt{6}}{2}$

7 0

3 years ago