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luda_lava [24]
3 years ago
8

Natalie and phil are running for 6th grade class president. Natalie receives 16 votes, and phil receives 12 votes.

Mathematics
2 answers:
sleet_krkn [62]3 years ago
5 0
Natalie because Natalie has more votes
lys-0071 [83]3 years ago
5 0

Answer:

Natalie win as the 6th grade class president

Step-by-step explanation:she win by 4 points after Phil and Natalie has 16 votes and Phil has 12 votes

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|x+5|+20=4 Needs to show work on how you came up with the answer.
arlik [135]

Answer:

No solution

Step-by-step explanation:

So we have the equation:

|x+5|+20=4

First, subtract 20 from both sides:

|x+5|=-16

Now, we can stop. Recall that absolute value will always <em>always</em> give a positive answer.

Since this equals -16, this means that there is no solution.

And we're done!

5 0
2 years ago
A University wanted to find out the percentage of students who felt comfortable reporting cheating by their fellow students. A s
Alla [95]

Answer:

The point estimate for this problem is 0.48.

Step-by-step explanation:

We are given that a University wanted to find out the percentage of students who felt comfortable reporting cheating by their fellow students.

A survey of 2,800 students was conducted and the students were asked if they felt comfortable reporting cheating by their fellow students. The results were 1,344 answered "Yes" and 1,456 answered "no".

<em>Let </em>\hat p<em> = proportion of students who felt comfortable reporting cheating by their fellow students</em>

<u></u>

<u>Now,  point estimate (</u>\hat p<u>) is calculated as;</u>

                               \hat p=\frac{X}{n}

where, X = number of students who answered yes = 1,344

            n = number of students surveyed = 2,800

So, Point estimate (\hat p)  =  \frac{1,344}{2,800}

                                     =  <u>0.48 or 48%</u>

5 0
3 years ago
If the local linear approximation of f(x) = 2cos x + e^2x at x = 2 is used to find the approximation for f(2.1), then the % erro
yKpoI14uk [10]

<u>Answer-</u>

The % error of this approximation is 1.64%

<u>Solution-</u>

Here,

\Rightarrow f(x) = 2\cos x + e^{2x}

\Rightarrow f'(x) = -2\sin x + 2e^{2x}

And,

\Rightarrow f(2) = 2\cos 2 + e^{4}

\Rightarrow f'(2) = -2\sin 2 + 2e^{4}

Taking (2, f(2)) as a point and slope as, f'(2), the function would be,

\Rightarrow y-y_1=m(x-x_1)

\Rightarrow y-(2\cos 2 + e^{4})=(-2\sin 2 + 2e^{4})(x-2)

\Rightarrow y=(-2\sin 2 + 2e^{4})(x-2)+(2\cos 2 + e^{4})

The value of f(2.1) will be

\Rightarrow y=(-2\sin 2 + 2e^{4})(2.1-2)+(2\cos 2 + e^{4})

\Rightarrow y=(-2\sin 2 + 2e^{4})(0.1)+(2\cos 2 + e^{4})

\Rightarrow y=64.5946

According to given function, f(2.1) will be,

\Rightarrow f(2.1) = 2\cos 2.1 + e^{2(2.1)}

\Rightarrow f(2.1) = 65.6766

\therefore \%\ error=\dfrac{65.6766-64.5946}{65.6766}=0.0164=1.64\%

5 0
3 years ago
1.625 rounded to the nearest hundredth
Mumz [18]
1.625 rounded to the nearest hundredth is 1.63
4 0
3 years ago
Read 2 more answers
6 is what percent of 96
sweet [91]
0.06 times 96 equals 5.76
4 0
2 years ago
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