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Ket [755]
3 years ago
5

Find the area of a regular hexagon with an apothem 8.7 centimeters long and a side 10 centimeters long. Round your answer to the

nearest tenth.
Mathematics
2 answers:
natulia [17]3 years ago
5 0

Answer:

261 cm²

Step-by-step explanation:

The area of the hexagon is 6 times the area of one of the triangles. The area of a triangle is base × height ÷ 2.

A = 6(8.7)10 ÷ 2

A = 261 cm²

ludmilkaskok [199]3 years ago
4 0

Answer:

Step-by-step explanation:

A regular hexagon is made up of six triangles having a height of 8.7cm and a base of 10cm. So the area of the hexagon is 6 times the area of one of the triangles. Since the area of a triangle is bh/2 we have

A=6(8.7)10/2

A=261cm^2

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What is the area of the rectangle? shoe your work! do not round anything until the very end and round your final answer to the t
weeeeeb [17]

Answer:

The area of the rectangle is 42 units^2

Step-by-step explanation:

we know that

The area of rectangle is equal to

A=LW

In this problem

AB=DC

BC=AD

see the attached figure with letters to better understand the problem

we have that

L=BC\\W=AB

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have the points

A(2,-1),B(5,2),C(12,-5),D(9,-8)

<em>Find out the distance BC</em>

we have

B(5,2),C(12,-5)

substitute in the formula

d=\sqrt{(-5-2)^{2}+(12-5)^{2}}

d=\sqrt{(-7)^{2}+(7)^{2}}

d_B_C=\sqrt{98}\ units

<em>Find out the distance AB</em>

we have

A(2,-1),B(5,2)

substitute in the formula

d=\sqrt{(2+1)^{2}+(5-2)^{2}}

d=\sqrt{(3)^{2}+(3)^{2}}

d_A_B=\sqrt{18}\ units

<em>Find out the area</em>

A=(L)(W)

we have

L=d_B_C=\sqrt{98}\ units

W=d_A_B=\sqrt{18}\ units

substitute

A=(\sqrt{98})(\sqrt{18})=42.0\ units^2

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