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Ket [755]
3 years ago
5

Find the area of a regular hexagon with an apothem 8.7 centimeters long and a side 10 centimeters long. Round your answer to the

nearest tenth.
Mathematics
2 answers:
natulia [17]3 years ago
5 0

Answer:

261 cm²

Step-by-step explanation:

The area of the hexagon is 6 times the area of one of the triangles. The area of a triangle is base × height ÷ 2.

A = 6(8.7)10 ÷ 2

A = 261 cm²

ludmilkaskok [199]3 years ago
4 0

Answer:

Step-by-step explanation:

A regular hexagon is made up of six triangles having a height of 8.7cm and a base of 10cm. So the area of the hexagon is 6 times the area of one of the triangles. Since the area of a triangle is bh/2 we have

A=6(8.7)10/2

A=261cm^2

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6 0
1 year ago
Quadrilateral LMNO has diagonals that intersect at point P. If LP=NP, MP = y + 25, and OP = 5y + 29, find the length of MO such
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I saw the image of this problem.

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