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-BARSIC- [3]
2 years ago
11

Which is a negatively skewed distribution?

Mathematics
1 answer:
Airida [17]2 years ago
4 0

Step-by-step explanation:

0c,02,4,6,8,10,12,14,16,18,20,22,24,26,28,30

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What is the length of XY
cestrela7 [59]

As we can see the given diagram represents an isosceles trapezoid.

So we can say from the properties of isosceles trapezoid.

xw=yz

y+6=12\\ \\ y=12-6\\ \\ y=6

As the required side XY has a length y+1, So we can write

Length  \ of \  XY=y+1=6+1\\ \\ \ Length  \ of \  XY=7\\

3 0
3 years ago
Read 2 more answers
Which expression is equivalent to sec^2x − 1? a. cot2x b. tan2x c. csc2x d. cos2x
Nesterboy [21]
Sec^2 x - 1 = tan^2x

Proof:
Sec^2x = 1+ tan^2x

1/cos^2x = 1 + sin^2x/cos^2x

<span>1/cos^2x - sin^2x/cos^2x = 1
</span>Using common denominator:
(1-sin^2x)/cos^2x = 1
sin^2x + cos^2 x = 1
cos^2 x = 1 - sin^2x
Substituting : 
cos^2x/<span>cos^2x = 1
</span>1 = 1
Left hand side = right hand side 
4 0
3 years ago
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Solve this system of equations <br> -2x+5y+4z=-4<br> -5x-y+z=-1<br> 2y+2z=-4
Shalnov [3]

Answer:

x = -1, y = 2 and z = -4.

Step-by-step explanation:

-2x + 5y + 4z = -4   ......(A)

-5x - y + z = -1   .............(B)

2y + 2z = -4..................(C)         Multiply (A) by 5 and (B) by -2:

-10x + 25y + 20z = -20 ....(D)

10x  + 2y - 2z = 2 ..............(E)    Adding D + E:

27y + 18z = -18    Dividing by 9:

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-y = -2

y = 2.

Substitute for y is (C):

4 + 2z = -4

2z = -8

z = -4.

Substitute for y and z in (A):

-2x + 5(2) + 4(-4) = -4  

-2x = -10 + 16 - 4 = 2

x = -1.

3 0
4 years ago
the windows on a building are proportional to the size of the building. the height of each is 18in and the width is 11in if the
Elena-2011 [213]
You can set this up as 2 fractions equal to each other, like ratios.

18/11=108/x

Cross multiply and you get 18x=1,188

Now divide both sides by 18 and get x.

x=66.

If the height of the building is 108ft, the width is 66ft.
4 0
3 years ago
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Equation<br> Number of Solutions<br> 6(2.1 + 1) - 2 = 12.1 + 4<br> How many solutions does it have?
jek_recluse [69]
Infinite solutions!!!!
7 0
3 years ago
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