All categories

1 year ago

A ship is stationary at sea.

1 answer:

7 0

Bearing is a topic that deals with the distance and location of a given object with respect to a reference point. Thus in the given question, the ship is 57.23 km to the yacht.

Bearing is a topic that considers the distance and position of a given object with respect to a reference point. Thus the angles are usually measured with reference to the north pole.

Thus to solve the given question, let the required distance be represented by x.

Applying the cosine rule, we have;

$c^{2}$ = $a^{2}$ + $b^{2}$ - 2ab Cos C

The angle C between the line from ship to tugboat and from tugboat to yacht can be determined as;

C = $10^{o}$ + $40^{o}$

C = $50^{o}$

Thus,

$c^{2}$ = $36^{2}$ + $27^{2}$ + 2(36 x 27) Cos $50^{o}$

= 1296 + 729 + 1944(0.6429)

= 2025 + 1249.8

$c^{2}$ = 3274.8

c = $\sqrt{3274.8}$

= 57.2259

c = 57.23

Therefore, the distance from the ship to the yacht is 57.23 km.

For more clarifications on Bearing, visit: brainly.com/question/22013596

#SPJ1

Kindly contact a 1-on-1 tutor if more explanations are needed.

You might be interested in

Kaden, Keith, and Kipp compete in a series of daily 3-way races. For each race, the probability that Kaden wins is 1/6, the prob

BlackZzzverrR [31]

9514 1404 393

Answer:

3/5

Step-by-step explanation:

Let a, b, c represent the probability of a win by Kaden, Keith, and Kipp, respectively.

P(bc' | a') = P(a'bc')/P(a')

P(bc' | a') = (1/2)/(1 -1/6) = (3/6)/(5/6) = 3/5

The probability is 3/5 that Keith beats Kipp when Kaden doesn't win.

4 0

2 years ago

Find the slope of the line passing through the points (-6,7) and (-8,5)

kykrilka [37]

Answer:

Slope = 1

Step-by-step explanation:

4 0

2 years ago

A group of five people are all working on the same mathematics problem. On the night before it is due, they call each other to d

UkoKoshka [18]

Answer:

Minimum number of calls = 10

Step-by-step explanation:

Lets name the five people as A,B,C,D and E.

On the night before ,each person talks to every other person atleast once that means A would talk to B,C,D and E atleast once.

Lets start with A. He would talk to other 4 people which means there would be 4 phone calls made.

Now lets take B. He can talk to A,C,D and E. But A has already talked to C therefore to get minimum number of phone calls , B need not call A again. So he calls only C,D and E.

In case of C using similar logic he need to talk to only D and E.

For D , he talks to E alone.

E does not have to talk to anyone as he has already talked to everyone atleast once.

Total calls = 4 + 3 + 2 + 1

= 10

5 0

3 years ago

A rectangle has perimeter 28cm. Its area is 42sq.cm. Determine the dimensions of the rectangle. Include a diagram in your soluti

yawa3891 [41]

The dimensions of the rectangle are: b=9.65 cm and h=4.35 cm or b=4.35 cm and h= 9.65 cm.

<h3>Quadrilaterals</h3>

There are different types of quadrilaterals, for example, square, rectangle, rhombus, trapezoid, and parallelogram. Each type is defined accordingly to its length of sides and angles. For example, in a rectangle, the opposite sides are equal and parallel and their interior angles are equal to 90°.

The area of a rectangle is equal to base x height (A=bh). The perimeter of a geometric figure is the sum of its sides. Thus, for a rectangle, the perimeter is 2b+2h.

<h3>System of Linear Equations</h3>

System of linear equations is the given term math for two or more equations with the same variables. The solution of these equations represents the point at which the lines intersect.

The question gives:

Perimeter=28cm

Area= 42 cm²

If the perimeter is the sum of all sides of the rectangle, you have:

Perimeter= 2b+2h=28

If the area of the rectangle is 42cm², you have:

Area=bh=42 cm²

You can write a system of linear equations.

2b+2h=28 (1)

bh=42 (2)

From equation 2, you have $b=\frac{42}{h}$ . Then, you can replace it in equation 1.

$2*\frac{42}{h}+2h=28 \\ \\ 84+2h^2=28h\\ \\ 2h^2-28h+84=0 \; dividing\; by\; 2\\ \\ h^2-14h+42=0$

Now, you should solve the quadratic equation.

$h_{1,\:2}=\frac{-\left(-14\right)\pm \sqrt{\left(-14\right)^2-4\cdot \:1\cdot \:42}}{2\cdot \:1}$

$h_{1,\:2}=\frac{-\left(-14\right)\pm \:2\sqrt{7}}{2\cdot \:1}$

$h_1=\frac{-\left(-14\right)+2\sqrt{7}}{2\cdot \:1}=7+\sqrt{7}=9.65 cm$

$h_2=\frac{-\left(-14\right)-2\sqrt{7}}{2\cdot \:1}=7-\sqrt{7}=4.35cm$

If h1=9.65 cm, then $b_1=\frac{42}{9.65} =4.35 cm$ , and if h2=4.35 cm, then $b_1=\frac{42}{4.35} =9.65 cm$ .

Read more about the quadratic function here:

brainly.com/question/1497716

#SPJ1

8 0

1 year ago

Your company gives you a cell phone plan which allows you 600 minutes to talk per month. So far this month, you have used 330 mi

Evgen [1.6K]

The answer is C) 10x + 330 ≤ 600.
We use the ≤ since you are allowed to use the 600th minute.
When we subtract 330 from both sides, it makes a bit more sense
10x ≤ 270
270 is the number of minutes left your plan since you've already used 330, and you have 10 days left in the month.

3 0

2 years ago