Answer:
16.25% was spent on food
Step-by-step explanation:
Step one
given data
A family spends $520 every month on food
The family's income is $3200 Monthly
Required
We want to find the percentage of the income spent on food only
Step two
percentage spent on food= amount spent on food/income*100
percentage spent on food= 520/3200*100
percentage spent on food= 0.1625*100
percentage spent on food= 16.25%
=16.25%
9514 1404 393
Answer:
a) w(4w-15)
b) w²
c) w(4w -15) = w²
d) w = 5
e) 5 by 5
Step-by-step explanation:
a) If w is the width, and the length is 15 less than 4 times the width, then the length is 4w-15. The area is the product of length and width.
A = w(4w -15)
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b) If w is the side length, the area of the square is (also) the product of length and width:
A = w²
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c) Equating the expressions for area, we have ...
w(4w -15) = w²
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d) we can subtract the right side to get ...
4w² -15w -w² = 0
3w(w -5) = 0
This has solutions w=0 and w=5. Only the positive solution is sensible in this problem.
The side length of the square is 5 units.
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e) The rectangle is 5 units wide, and 4(5)-15 = 5 units long.
The rectangle and square have the same width and the same area, so the rectangle must be a square.
Given the angle:
-660°
Let's find the coterminal angle from 0≤θ≤360.
To find the coterminal angle, in the interval given, let's keep adding 360 degrees to the angle until we get the angle in the interval,
We have:
Coterminal angle = -660 + 360 = -300 + 360 = 60°
Therefore, the coterminal angle is 60°.
Since 60 degrees is between 0 to 90 degrees, is is quadrant I.
60 degrees lie in Quadrant I.
Also since it is in quadrant I, the reference angle is still 60 degrees.
ANSWER:
The coterminal angle is 60°, which lies in quadrant I, with a reference angle of 60°
(1, 9) and (11,1)
slope
= (9 - 1)/(1 - 11)
= 8 /-10
= -4/5
= - 0.8
answer
slope = - 0.8
Answer:
3
Step-by-step explanation:
24 + (-1) = 23, 12 + (-2) = 10, 8 + (-3) = and 6 + (- 4) = 2, none of the sums are equal to 3, therefore b = 3 would give a prime quadratic. The correct answer is then A. 3