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3 years ago

What is the y-intercept of the graph of the function f(x)=x^2+3x+5?

Mathematics

2 answers:

marta [7]3 years ago

8 0

Answer:

y int = (0,5)

Step-by-step explanation:

hope this helps

Dima020 [189]3 years ago

5 0

Y=(0,5)

So it is the last one choose that
And that is the correct answer

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How many times will 1/5 go into 37

Marat540 [252]

1/5 goes into 37 185 times:

37 / (1/5) = 37*(5/1)=185

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4 years ago

What is the absolute value of 0.6?

Nesterboy [21]

The absolute value of 0.6 is 0.6 beacause its the same thing

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3 years ago

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A stamp collector has 55 stamps from the United States, 30 stamps from Canada, and 15 from Mexico. If he were to close his eyes

Vinvika [58]

6% chance I think but I’m not sure

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3 years ago

Integrate the following

enot [183]

I suppose you mean to have the entire numerator under the square root?

$\displaystyle\int_2^4\frac{\sqrt{x^2-4}}{x^2}\,\mathrm dx$

We can use a trigonometric substitution to start:

$x=2\sec t\implies\mathrm dx=2\sec t\tan t\,\mathrm dt$

Then for $x=2$ , $t=\sec^{-1}1=0$ ; for $x=4$ , $t=\sec^{-1}2=\frac\pi3$ . So the integral is equivalent to

$\displaystyle\int_0^{\pi/3}\frac{\sqrt{(2\sec t)^2-4}}{(2\sec t)^2}(2\sec t\tan t)\,\mathrm dt=\int_0^{\pi/3}\frac{\tan^2t}{\sec t}\,\mathrm dt$

We can write

$\dfrac{\tan^2t}{\sec t}=\dfrac{\frac{\sin^2t}{\cos^2t}}{\frac1{\cos t}}=\dfrac{\sin^2t}{\cos t}=\dfrac{1-\cos^2t}{\cos t}=\sec t-\cos t$

so the integral becomes

$\displaystyle\int_0^{\pi/3}(\sec t-\cos t)\,\mathrm dt=\boxed{\ln(2+\sqrt3)-\frac{\sqrt3}2}$

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3 years ago

Someone has conducted a study to see if there is increased risk of getting lung cancer if you work in a coal mine. In group 1, 3

AleksandrR [38]

Answer:

Sample relative risk is 10.

Step-by-step explanation:

We are given the following in the question:

Group 1 of coal miners: 30 out of 150 get lung cancer.

$\text{P(Lung cancer for coal miner)} = \dfrac{30}{150} = \dfrac{1}{5}$

Group 2 of non-coal miners: 5 out of 250 get lung cancer

$\text{P(Lung cancer for non-coal miner)} = \dfrac{5}{250} = \dfrac{1}{50}$

Sample relative risk:

It is the ratio of probability of an outcome in an exposed group to the probability of an outcome in an unexposed group.

Sample relative risk =

$\dfrac{\text{P(lung cancer for coal miner)}}{\text{P(lung cancer for non coal miner)}}\\\\=\dfrac{\frac{1}{5}}{\frac{1}{50}} = \dfrac{50}{5} = 10$

Thus, sample relative risk is 10.

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3 years ago