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3 years ago

What is the solution set for the inequality below? 8x – 3 < 29

Mathematics

1 answer:

Volgvan3 years ago

4 0

Answer:

$solution \: set = \{ ... - 2, \: - 1, \: 0, \: 1, \: 2, \: 3\}$

Step-by-step explanation:

$8x - 3 < 29 \\ \\ 8x < 29 + 3 \\ \\ 8x < 32 \\ \\ x < \frac{32}{8} \\ \\ x < 4 \\ \\ solution \: set = \{ ... - 2, \: - 1, \: 0, \: 1, \: 2, \: 3\}$

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Henry knows that the circumference of a circle is 18mc006-1.jpg inches. What is the area of the circle?

lesantik [10]

The complete question is:
Henry knows that the circumference of a circle is 18π inches. What is the area of the circle?

Solution:
Circumference (C) of the circle can be written as:

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Using this value of radius, we can find the Area(A) of the circle.

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3 years ago

Hunter had 3⁄8 of a pizza. He gave 2⁄3 of the pizza to his friend Taylor. What fraction of the whole pizza did Taylor get?

Nikitich [7]

Answer:

1/4

Step-by-step explanation:

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3 years ago

I need help really quick

nasty-shy [4]

Answer:

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Write and equation for the shift of the parent graph y=1/x

SashulF [63]

You can think of this equation as $\bf f(x)=\cfrac{1}{x}\implies f(x)=(x)^{-1}$

and thus apply the transformations to it as such

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\$

$\bf \bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

1) D = 2, C = +3

2) D = -12, C = -2

3) C = +6, D = 3

4) C = -7, D = -7

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3 years ago