All categories

3 years ago

. Un bloque de hierro tiene 5.0 cm de largo, 3.0 cm de alto y 4.0 cm de ancho y pesa 474 g ¿Cuál es la densidad del hierro?

Mathematics

1 answer:

mrs_skeptik [129]3 years ago

8 0

Answer:

the density of the iron is 7.9 g /cm^3

Step-by-step explanation:

The computation of the density of the iron is shown below:

Density = weight ÷ volume

= 474 ÷ (5 × 3 × 4)

= 474 ÷ 60

= 7.9 g /cm^3

Hence, the density of the iron is 7.9 g /cm^3

You might be interested in

Help anyone ?????????

elena-14-01-66 [18.8K]

Ans: -4.3

Integers are all whole numbers negative, positive, and 0

Hope this helped :)

7 0

4 years ago

Read 2 more answers

(will give brainliest!)

Flura [38]

Answer:

D) cot(C) = 1/2.

Step-by-step explanation:

We can go through each choice and examine is validity.

Choice A)

We have:

$\displaystyle \sec B=\frac{3}{7}$

Recall that secant is the ratio of the hypotenuse to the adjacent.

With respect to B, the adjacent is 6 and the hypotenuse is 7.

Therefore, sec(B) should be 7/6 instead.

A is incorrect.

Choice B)

We have:

$\displaystyle \cot B=\frac{3}{2}$

Cotangent is the ratio of the adjacent side to the opposite.

With respect to B, the adjacent side is 6 and the opposite side is 3.

Therefore, cot(B) = 6/3 = 2.

B is incorrect.

Choice C)

C is incorrect for the reasons listed in A.

Choice D)

We have:

$\displaystyle \cot C=\frac{1}{2}$

Again, cotangent is the ratio of the adjacent side to the opposite.

With respect to C, the adjacent side is 3 and the opposite side is 6.

So, cot(C) = 3/6 = 1/2.

Therefore, D is the correct choice!

8 0

3 years ago

If y= -3x7+2x3+ x, the derivative of y with respect to x is

larisa [96]

Answer:

$\frac{dy}{dx}$ = - 21 $x^{6}$ + 6x² + 1

Step-by-step explanation:

Differentiate each term using the power rule

$\frac{d}{dx}$ (a $x^{n}$ ) = na $x^{n-1}$

Given

y = - 3 $x^{7}$ + 2x³ + x , then

$\frac{dy}{dx}$ = (7 × - 3 ) $x^{6}$ + (3 × 2)x² + (1 × 1 ) $x^{0}$

= - 21 $x^{6}$ + 6x² + 1

8 0

3 years ago

How do I solve question 6 through 8?<br> Solve for me

rewona [7]

The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

<h3>How to determine the functions?</h3>

A quadratic function is represented as:

y = a(x - h)^2 + k

<u>Question #6</u>

The vertex of the graph is

(h, k) = (-1, 2)

So, we have:

y = a(x + 1)^2 + 2

The graph pass through the f(0) = -2

So, we have:

-2 = a(0 + 1)^2 + 2

Evaluate the like terms

a = -4

Substitute a = -4 in y = a(x + 1)^2 + 2

y = -4(x + 1)^2 + 2

<u>Question #7</u>

The vertex of the graph is

(h, k) = (2, 1)

So, we have:

y = a(x - 2)^2 + 1

The graph pass through (1, 3)

So, we have:

3 = a(1 - 2)^2 + 1

Evaluate the like terms

a = 2

Substitute a = 2 in y = a(x - 2)^2 + 1

y = 2(x - 2)^2 + 1

<u>Question #8</u>

The vertex of the graph is

(h, k) = (1, -2)

So, we have:

y = a(x - 1)^2 - 2

The graph pass through (0, -3)

So, we have:

-3 = a(0 - 1)^2 - 2

Evaluate the like terms

a = -1

Substitute a = -1 in y = a(x - 1)^2 - 2

y = -(x - 1)^2 - 2

Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2