If I am not wrong,the slope of the hillside should be increasing constantly.
Answer:
The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
Suppose a sample of 1067 floppy disks is drawn. Of these disks, 74 were defective.
This means that
80% confidence level
So , z is the value of Z that has a pvalue of , so .
The lower limit of this interval is:
The upper limit of this interval is:
The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).
Answer:
97 years
Step-by-step explanation:
20,000 - 15,862 = 4,138
y × 100 = 15,862 × 1.3
100y = 20620.6
100y ÷ 100 = 20620.6 ÷ 100
y = 206.206
20,000 ÷ 206.206 = 96.9903882525
96.9903882525 rounds to 97
3/9=1/3. To get from 3 to 9, multiply by 3. To maintain the same fraction, also multiply the numerator i.e 1 by 3.