Answer:
2.6i
Step-by-step explanation:
undo the - by making it: √-6.76= √6.76 x √-1
then, √-1 would be converted to imaginary number -> i
now rewrite it as √6.76 x i or i√6.76 which is the same as the squareroot of 6.76 which is 2.6 times i.
Then just write your final answer as 2.6i
The Greatest Common factor(GCF) of -2x^2-4x-6 is -2(x+1)(x-3)
<h3>What is Greatest Common Factor?</h3>
The greatest common factor (GCF) is the largest factor two or more numbers have in common
From the question,
-2x^2-4x-6
By collecting like terms
-2(x^2-2x-3)
By factoring x^2-2x-3
-2(x^2-3x+1x-3)
Collecting like terms
-2(x^2-3x)+(x-3)
-2(x(x-3)+1(x-3))
-2(x+1)(x-3)
hence -2(x+1)(x-3) is the Greatest Common factor of -2x^2-4x-6 is
Learn more about Greatest Common factor on:brainly.com/question/219464
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By counting grid squares, we see the library is 5 miles north and 6 miles east of Ashley's house. Using the Pythagorean theorem, we can find the straight-line distance to be
.. d = √(5^2 +6^2)
.. = √(25 +36)
.. = √61 . . . . . miles
.. ≈ 7.81 . . . . miles
Answer:
The figure is attached and the total distance is 1031 feet.
Step-by-step explanation:
The graph is indicated in the attached figure.
For calculation of distance consider following
Point Flagpole is (0,0)
Point Clue1 is (0,5)
Point Clue2 is (6,0)
Point Clue3 is (0,-5)
So the distance is calculated as follows
![d_{T}=[d_{FP\ to\ Clue1}+d_{Clue1\ to\ Clue2}+d_{Clue2\ to\ Clue3}]*distance\ per\ unit\\d_{T}=[\sqrt{(Clue1_x-FP_x)^2+(Clue1_y-FP_y)^2}+\sqrt{(Clue2_x-Clue1_x)^2+(Clue2_y-Clue1_y)^2}+\sqrt{(Clue3_x-Clue2_x)^2+(Clue3_y-Clue2_y)^2}]**distance\ per\ unit\\](https://tex.z-dn.net/?f=d_%7BT%7D%3D%5Bd_%7BFP%5C%20to%5C%20Clue1%7D%2Bd_%7BClue1%5C%20to%5C%20Clue2%7D%2Bd_%7BClue2%5C%20to%5C%20Clue3%7D%5D%2Adistance%5C%20per%5C%20unit%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B%28Clue1_x-FP_x%29%5E2%2B%28Clue1_y-FP_y%29%5E2%7D%2B%5Csqrt%7B%28Clue2_x-Clue1_x%29%5E2%2B%28Clue2_y-Clue1_y%29%5E2%7D%2B%5Csqrt%7B%28Clue3_x-Clue2_x%29%5E2%2B%28Clue3_y-Clue2_y%29%5E2%7D%5D%2A%2Adistance%5C%20per%5C%20unit%5C%5C)
Substituting the values
![d_{T}=[\sqrt{(0-0)^2+(5-0)^2}+\sqrt{(6-0)^2+(0-5)^2}+\sqrt{(0-6)^2+(-5-0)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{(0)^2+(5)^2}+\sqrt{(6)^2+(-5)^2}+\sqrt{(-6)^2+(-5)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{0+25}+\sqrt{36+25}+\sqrt{36+25}]*50 \text{ feet}\\d_{T}=[\sqrt{25}+\sqrt{61}+\sqrt{61}]*50 \text{ feet}\\d_{T}=[5+7.81+7.81]*50 \text{ feet}\\d_{T}=[20.62]*50 \text{ feet}\\d_{T}=1031 \text{ feet}\\](https://tex.z-dn.net/?f=d_%7BT%7D%3D%5B%5Csqrt%7B%280-0%29%5E2%2B%285-0%29%5E2%7D%2B%5Csqrt%7B%286-0%29%5E2%2B%280-5%29%5E2%7D%2B%5Csqrt%7B%280-6%29%5E2%2B%28-5-0%29%5E2%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B%280%29%5E2%2B%285%29%5E2%7D%2B%5Csqrt%7B%286%29%5E2%2B%28-5%29%5E2%7D%2B%5Csqrt%7B%28-6%29%5E2%2B%28-5%29%5E2%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B0%2B25%7D%2B%5Csqrt%7B36%2B25%7D%2B%5Csqrt%7B36%2B25%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B25%7D%2B%5Csqrt%7B61%7D%2B%5Csqrt%7B61%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B5%2B7.81%2B7.81%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B20.62%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D1031%20%5Ctext%7B%20feet%7D%5C%5C)
So the total distance travelled is 1031 feet.
