Question

If f(1) = 2 and f(n+1) = f(n)^2 – 3 then find the value of f(3).

Answer 1

Answer:

The value of f(3) = -2.

Step-by-step explanation:

First of all, let's find f(2).

$f(n+1)=f(n)^{2}-3$

$f(1+1)=f(1)^{2}-3$

$f(2)=f(1)^{2}-3=2^{2}-3=1$

Now, we can find f(3):

$f(2+1)=f(2)^{2}-3$

$f(3)=f(2)^{2}-3=1^{2}-3=-2$

Therefore, the value of f(3) = -2.

I hope it helps you!